Refer to the diagram shown.
F = 65 N, the force exerted by Dwight.
The horizontal component of the force is
65 cos(50°) = 41.8 N
The vertical component of the force is
65 sin(50°) = 49.8 N
Answer:
Horizontal: 41.8 N
Vertical: 49.8 N
F = 65 N, the force exerted by Dwight.
The horizontal component of the force is
65 cos(50°) = 41.8 N
The vertical component of the force is
65 sin(50°) = 49.8 N
Answer:
Horizontal: 41.8 N
Vertical: 49.8 N