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gladu [14]
3 years ago
7

If you get too many fouls, you may not be able to play in the rest of the game.

Physics
2 answers:
klasskru [66]3 years ago
7 0
True!!! Djsshsnnebsbss. Ssnsnsnsndbdeb
trapecia [35]3 years ago
4 0

Answer:

In the NBA that's true

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How to answer this question?
laila [671]

Answer:

measure the vector diagram first

5 0
3 years ago
When testing a plugged-in but partly disassembled toaster, you should push the rack down with a
Sphinxa [80]
A wooden stick would be best.
The wire and the wrench are both metal and therefore are able to conduct electricity.
Using your finger is obviously dangerous.
Wood is not a conductor so it is the best answer.
4 0
3 years ago
What is the velocity of an object that has a mass of 2.5 kg and a momentum of 1,000 kg · m/s?
N76 [4]
Using the momentum formula p=mv, it can be determined that v=p/m. Therefore 1000/2.5 = 400. The object is going 400m/s
7 0
4 years ago
Read 2 more answers
A 0.5 m3 container is filled with a fluid whose specific volume is 0.001 m3/kg. At standard gravitational acceleration, the cont
xenn [34]

Answer: the contents of this container weighs 4905 kg.m/s²

Explanation:

Given that;

volume of a container V = 0.5 m³

we know that standard gravitational acceleration g = 9.81 m/s²

specific volume of liquid filled in the container v = 0.001 m³/kg

now we express the equation for weight of the container.

W = mg

W = (pV)g

W = Vg / ν

so we substitute

W =  (0.5 m³)(9.81 m/s ) / 0.001 m³/kg

W = 4.905 / 0.001

W = 4905 kg.m/s²

Therefore, the contents of this container weighs 4905 kg.m/s²

5 0
3 years ago
How far can a sound wave travel in 90 seconds when the ambient air temperature is 10 C?
Ksju [112]

Answer:

s = 30330.7 m = 30.33 km

Explanation:

First we need to calculate the speed of sound at the given temperature. For this purpose we use the following formula:

v = v₀√[T/273 k]

where,

v = speed of sound at given temperature = ?

v₀ = speed of sound at 0°C = 331 m/s

T = Given Temperature = 10°C + 273 = 283 k

Therefore,

v = (331 m/s)√[283 k/273 k]

v = 337 m/s

Now, we use the following formula to calculate the distance traveled  by sound:

s = vt

where,

s = distance traveled = ?

t = time taken = 90 s

Therefore,

s = (337 m/s)(90 s)

<u>s = 30330.7 m = 30.33 km</u>

6 0
3 years ago
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