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Alla [95]
3 years ago
8

Hclo is a weak acid (ka=4.0x10^-8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.037 m in na

clo at 25 c
Chemistry
1 answer:
ankoles [38]3 years ago
7 0

<u>Given:</u>

Concentration of NaClO = 0.037 M

ka (HClO) = 4.0*10⁻⁸

<u>To determine:</u>

The pH of the NaClO solution

<u>Explanation:</u>

The hydrolysis of the weak base can be represented by the ICE table shown below-

                ClO-      +     H2O    ↔    HClO    +       OH-

Initial        0.037M                              0                    0

Change         -x                                 +x                  +x

Equilibrium  (0.037-x)                        x                     x

kb  = kw/ka =  [HClO][OH-]/[ClO-]

10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)

x = [OH-] = 9.62*10⁻⁵

p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02

pH = 14-p[OH-] = 14 - 4.02 = 9.98

Ans: pH of the solution is 9.98


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How many moles are 3.20 x102 formula units of calcium iodide?
DedPeter [7]

The number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

<h3>How to calculate number of moles?</h3>

The number of moles in the formula units of a substance is calculated by dividing the formula unit by Avogadro's number.

According to this question, 3.20 x 10² formula units are in calcium iodide. The number of moles is as follows:

no of moles = 3.20 x 10²² ÷ 6.02 × 10²³

no of moles = 0.53 × 10-¹

no of moles = 0.053 moles

Therefore, the number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

Learn more about number of moles at: brainly.com/question/12513822

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Question 2 of 50
wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

  1. Write the balanced chemical equation for the given reaction.
  2. Convert the mass of calcium carbonate into moles.
  3. Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
  4. Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

mol \ CaO \ = 0.2498 \ mol

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

\boxed {mass \ CaO \ = 14 \ g}

Learn More

  1. Learn more about stoichiometry brainly.com/question/12979299
  2. Learn more about mole conversion brainly.com/question/12972204
  3. Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

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3 years ago
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