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Alla [95]
3 years ago
8

Hclo is a weak acid (ka=4.0x10^-8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.037 m in na

clo at 25 c
Chemistry
1 answer:
ankoles [38]3 years ago
7 0

<u>Given:</u>

Concentration of NaClO = 0.037 M

ka (HClO) = 4.0*10⁻⁸

<u>To determine:</u>

The pH of the NaClO solution

<u>Explanation:</u>

The hydrolysis of the weak base can be represented by the ICE table shown below-

                ClO-      +     H2O    ↔    HClO    +       OH-

Initial        0.037M                              0                    0

Change         -x                                 +x                  +x

Equilibrium  (0.037-x)                        x                     x

kb  = kw/ka =  [HClO][OH-]/[ClO-]

10⁻¹⁴/4*10⁻⁸ = x²/(0.037-x)

x = [OH-] = 9.62*10⁻⁵

p[OH-] = -log[OH-] = -log [9.62*10⁻⁵] = 4.02

pH = 14-p[OH-] = 14 - 4.02 = 9.98

Ans: pH of the solution is 9.98


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A piece of an unknown metal has a volume of 19.8 ml and a mass of 210.0 grams. The density of the metal is g/mL A piece of the s
leva [86]

<u>Answer:</u> The density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

<u>Explanation:</u>

To calculate the density of unknown metal, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}       ......(1)

Volume of unknown metal = 19.8 mL

Mass of unknown metal = 210.0 g

Putting values in equation 1, we get:

\text{Density of unknown metal}=\frac{210.0g}{19.8mL}\\\\\text{Density of unknown metal}=10.60g/mL

The density of the metal remains the same.

Now, calculating the volume of unknown metal, using equation 1, we get:

Density of unknown metal = 11.45 /mL

Mass of unknown metal = 86.0 g

Putting values in above equation, we get:

10.60g/mL=\frac{86.0g}{\text{Volume of unknown metal}}\\\\\text{Volume of unknown metal}=8.11mL

Hence, the density of the metal is 10.60 g/mL and the volume occupied by 86.0 grams is 8.11 mL

5 0
4 years ago
Calculate the number of mol of helium in a 2.01-L balloon at 29°C and 2.71 atm of pressure. Be sure to answer all parts. Imol
konstantin123 [22]

Answer:

0.220 mol He

Explanation:

Hello,

Based on the ideal gas equation of state:

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Best regards.

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Hope this helps you.

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The isotopes are the elements with same atomic number but different atomic mass or mass number

The mass number is denoted by Z

The mass number is denoted by A

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A = 110, N = 49 it means Z = Z - N = 110-49 = 61 So this is not isotope of indium

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4 years ago
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