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iVinArrow [24]
2 years ago
12

I'm very confused on Solubility and Temperature. Please Help!

Chemistry
1 answer:
lukranit [14]2 years ago
8 0
When a solid is added to a liquid, there exists a possibility that it will get dissolved in the solid. However, this depends on a lot of factors, like the temperature of the substances, the volume of the liquid, and the amount and nature of the solid to be dissolved.

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Classify each of the statements below as pertaining to viscosity or osmolarity.
Yuliya22 [10]
Viscosity is related to the parallel shear force acted by the fluid. In lay man's term, viscosity is the ease of how the fluid flows. The faster the flow is, the lower the viscosity (and vice versa). On the other hand, osmolarity pertains to the concentration of a component in a mixture expressed in number of solute particles per liter of the mixture.
7 0
2 years ago
(a) What property is used today for the order of the elements?
Gennadij [26K]

Answer:

I feel as though you are missing information to this question.

Explanation:

elements on the periodic table, today, are arranged based on physical properties, such as valence electrons, atomic mass, etc.

3 0
2 years ago
What is a chemical change?
PIT_PIT [208]
A chemical change is a change that results in new chemicals (the reactants underwent a chemical change which resulted in new products). 
an example of a chemical change is the burning of paper. An example of something that is not a chemical change is the melting of ice.
4 0
2 years ago
Is chocolate milk a pure substance or mixture
Valentin [98]
Mixture; it contains water, surgar, fat, protein, etc.
5 0
3 years ago
An unknown compound contains only C, H, and O. Combustion of 8.50 g of this compound produced 20.0 g CO2 and 5.46 g H2O. What is
Galina-37 [17]

Answer:

The answer to your question is: C₃H₄O

Explanation:

Data

CxHyOz = 8.5 g

CO2 = 20 g

H2O = 5.46 g

Reaction

             CxHyOz + O2     ⇒    CO2   +    H2O

CO2

    MW = 44g

                       44g CO2 ----------------- 12g of C

                        20g CO2 ----------------   x

                       x = (20 x 12) / 44

                       x = 5.45 g of C

                     # of moles = n = 5.45 / 12 = 0.454 mol of C

H2O

     MW = 18 g

                       18 g H2O ------------------- 2g of H

                       5.46 g    --------------------   x

                       x = (5.46 x 2) / 18 = 0.61 g of H

                       n = 0.61 / 1 = 0.61 moles of H2

Mass of O2

              mass CxHyOz = mass CO2 + mass H2 + mass O2

              mass O2 = 8.5 - 5.45 - 0.61

              mass O2 = 2.44g

              n = 2.44 / 16 = 0.153 mol of O2

Now, divide by the lowest number of moles

0.454 mol of C/ 0.153 = 2.97 ≈ 3

0.61 moles of H2/ 0.153 = 3.99 ≈ 4

0.153 mol of O2/ 0.153 =  1

Then, the empirical formula is: C₃H₄O

7 0
3 years ago
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