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Inga [223]
3 years ago
14

Please explain your answer! Thanks!

Chemistry
2 answers:
Yuri [45]3 years ago
8 0
Hello Gary!
*Sorry if I'm late*

Your answer is going to be 65.
Element A (which is actually Zinc) has the atomic number of 65. (I remember having got memorize this also).
Pretty much the explanation is that the number of patrons is equivalent to the element's atomic number!

Hope this helps!
Have a nice day :D
Dafna11 [192]3 years ago
7 0
65

Element A

Look at the periodic table:)
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A reactant decomposes with a half-life of 29.5 s when its initial concentration is 0.229 M. When the initial concentration is 0.
Dmitrij [34]

Answer :

The order of reaction is, 0 (zero order reaction).

The value of rate constant is, 0.00388Ms^{-1}

Explanation :

Half life : It is defined as the time in which the concentration of a reactant is reduced to half of its original value.

The general expression of half-life for nth order is:

t_{1/2}\propto \frac{1}{[A_o]^{n-1}}

or,

\frac{t_{1/2}_1}{t_{1/2}_2}=\frac{[A_2]^{n-1}}{[A_1]^{n-1}}

or,

n=\left(\frac{\log\frac{(t_{1/2})_1}{(t_{1/2})_2}}{\log\frac{(A)_2}{(A)_1}}\right )+1           .............(1)

where,

t_{1/2} = half-life of the reaction

n = order of reaction

[A] = concentration

As we are given:

Initial concentration of A = 0.229 M

Final concentration of A = 0.639 M

Initial half-life of the reaction = 29.5 s

Final half-life of the reaction = 82.3 s

Now put all the given values in the above formula 1, we get:

n=\left (\frac{\log \frac{29.5}{82.3}}{\log\frac{0.639}{0.229}}\right )+1

n=0.000196\approx 0

Thus, the order of reaction is, 0 (zero order reaction).

Now we have to determine the rate constant.

To calculate the rate constant for zero order the expression will be:

t_{1/2}=\frac{[A_o]}{2k}

When,

t_{1/2} = 29.5 s

[A_o] = 0.229 M

29.5s=\frac{0.229M}{2k}

k=0.00388Ms^{-1}

Thus, the value of rate constant is, 0.00388Ms^{-1}

4 0
3 years ago
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