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olga_2 [115]
2 years ago
9

How can trace fossils provide info on how the organism lived

Chemistry
1 answer:
iragen [17]2 years ago
5 0
Fossils provide a window in Earth's history by showing us how they existed in the past. They can be dated through several ways and can show us how animals and plants have evolved over millions of years. Also, fossils can help us better understand ancient disasters by the inclusion of elements (such as <span>volcanic ash or dust from major space object impacts) and how they affected the life on earth)</span>
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PLSS ANSWERRRR
const2013 [10]

Answer:

b

Explanation:

6 0
3 years ago
How many moles would 1.00 x10^23 molecules of methane represent
tester [92]

Answer:

Explanation:

1 x 10²³ molecules of methane

6.02 x 10²³ molecules of methane = 1 mole of methane

10²³ molecules of methane = 1 / 6.02 moles of methane

= .166 moles .

3 0
2 years ago
When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this pheno
Paraphin [41]

Answer:

The correct answer is option B.

Explanation:

When we increase number of molecules of reactant frequency of the molecular collision increases due to which effective collision between reactant molecules to form a product also increases, With this overall rate of the reaction increases.

Where as:

When we increase the temperature of the reactant molecules increase in average kinetic energy of the molecules is observed.

When we increase the activation energy of the reaction rate of the reaction slows down,

5 0
3 years ago
Active volcanoes are most likely to be found at what boundary
Svetradugi [14.3K]
Near plate boundries
5 0
2 years ago
2). H2S and SO2 as follows,(8pt)
Naddik [55]

Answer: 75.7 % yield

Explanation:

The balanced chemical equation is:

2H_2S+SO_2\rightarrow 3S+2H_2O  

According to stoichiometry :

68.2 g of H_2S will require = 64 g of SO_2

Thus 7.5 g of H_2S will require = \frac{64}{68.2}\times 7.5=7.0g of SO_2

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 68.2 g of give = 96 g of

Thus 7.5 g of H_2S give =\frac{96}{68.2}\times 7.5=10.5g  of S

% yield=\frac{\text{Actual yield}}{\text {Theoretical yield}}\times 100=\frac{7.95g}{10.5g}\times 100=75.7\%

Thus 75.7 % yield is there.

5 0
2 years ago
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