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olga_2 [115]
3 years ago
9

How can trace fossils provide info on how the organism lived

Chemistry
1 answer:
iragen [17]3 years ago
5 0
Fossils provide a window in Earth's history by showing us how they existed in the past. They can be dated through several ways and can show us how animals and plants have evolved over millions of years. Also, fossils can help us better understand ancient disasters by the inclusion of elements (such as <span>volcanic ash or dust from major space object impacts) and how they affected the life on earth)</span>
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What mass of agno3 can be dissolved in 250 g of water at 20 c?
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More information please
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4 years ago
Solutes lower the freezing point of water by:
il63 [147K]
Water molecules are constantly moving in Ice they move slower and are more tightly packed together and move at a slower pace to lower the freezing point you would have to find a solute that makes it harder for water to form crystals 
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3 years ago
Barium + Aluminum nitrate —&gt; makes what ?
Murljashka [212]

Answer:

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3 years ago
If I have 31 liters of helium in a balloon at 9°C and increase the temperature of the balloon to 28°C, what will the new volume
Ede4ka [16]

Answer: The new volume of the balloon is 33 liters while T2 is 301K

Explanation:

Initial volume of helium V1 = 31 liters

Initial temperature T1 = 9°C

Convert temperature in Celsius to Kelvin

( 9°C + 273°C = 280K)

Final temperature T2 = 28°C

( 28°C + 273°C = 301K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

31/280 = V2/301

To get the value of V2, cross multiply

V2 = (31 x 301) / 280

V2 = 9331 / 280

V2 = 33.325 liters (approximated to 33liters)

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8 0
4 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
Radda [10]

Answer is: activation energy of this reaction is 212,01975 kJ/mol.<span>
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁).<span>
k</span>₁ = 0,000643 1/s.<span>
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

<span> 1/T</span>₁ = 1/622 K = 0,0016 1/K.<span>
1/T</span>₂ = 1/666 K = 0,0015 1/K.<span>
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol </span>· (-0,0001 1/K).<span>
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

6 0
3 years ago
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