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kumpel [21]
3 years ago
13

Water enters a 2 m3 tank at a rate of 6 kg/s and is withdrawn at a rate of 2 kg/s. The tank is initially half full. What type of

process is this?
Physics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

This process is semicontinuous.

Explanation:

Given that,

Volume = 2 m³

Enter flow rate = 6 kg/s

Exit flow rate = 2 kg/s

The tank is initially half full.

We need to find what type of process

Using given data,

This process is not continuous because given enter and exit flow rate is not equal.

This process is semicontinuous and the water level in the tank does not reach a constant level.

Hence, This process is semicontinuous.

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when the mass of an object is increased it would decrease its acceleration in the force is left alone
mojhsa [17]

Answer:

See the explanation below.

Explanation:

This analysis can be easily deduced by means of Newton's second law which tells us that the sum of the forces or the total force on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = total force [N]

m = mass [kg]

a = acceleration [m/s²]

We must clear the acceleration value.

a=\frac{F}{m}

We see that the term of the mass is in the denominator, so that if the value of the mass is increased the acceleration decreases, since they are inversely proportional.

4 0
3 years ago
A 12.0-kilogram object is lifted from the ground to a height of 4.00 meters.
kow [346]

Answer:

3 j

Explanation:

12.0 kilo / 4.00 meters = 3 j

4 0
3 years ago
During a football game, the running back changes direction from running 4.5 m/s [N] to 4.5 m/s [S] over 8 s. What is the acceler
Nimfa-mama [501]

Explanation:

Take north to be positive and south to be negative.

a = (v − v₀) / t

a = (-4.5 m/s − 4.5 m/s) / 8 s

a = -1.125 m/s²

The acceleration is 1.125 m/s² south.

8 0
3 years ago
A 1.2 g pebble is stuck in a tread of a 0.76 m diameter automobile tire, held in place by static friction that can be at most 3.
Maksim231197 [3]

Answer:

v=33.764m/s

Explanation:

Given data

Mass m=1.2 g=0.0012 kg

diameter d=0.76 m

Friction Force F=3.6 N

To find

Velocity v

Solution

From the Centripetal force we know that

F_{c}=\frac{mv^{2} }{r}

Where m is mass

v is velocity

r is radius

Substitute the given values to find velocity v

So

F_{c}=\frac{mv^{2} }{r}\\v^{2}=\frac{F_{c}(r)}{m}\\ v=\sqrt{\frac{F_{c}(r)}{m}}\\ v=\sqrt{\frac{F_{c}(diameter/2)}{m}}\\v=\sqrt{\frac{(3.6N)(0.76/2)m}{(0.0012kg)}}\\v=33.764m/s

4 0
3 years ago
Cold plasma used in TVs is different from the solar plasma because ___________.
Arisa [49]

Answer: B i believe

Explanation:

5 0
4 years ago
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