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kumpel [21]
2 years ago
13

Water enters a 2 m3 tank at a rate of 6 kg/s and is withdrawn at a rate of 2 kg/s. The tank is initially half full. What type of

process is this?
Physics
1 answer:
NemiM [27]2 years ago
8 0

Answer:

This process is semicontinuous.

Explanation:

Given that,

Volume = 2 m³

Enter flow rate = 6 kg/s

Exit flow rate = 2 kg/s

The tank is initially half full.

We need to find what type of process

Using given data,

This process is not continuous because given enter and exit flow rate is not equal.

This process is semicontinuous and the water level in the tank does not reach a constant level.

Hence, This process is semicontinuous.

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Two long, parallel wires are separated by 2.2 mm. Each wire has a 32-AA current, but the currents are in opposite directions. Pa
Alex

Answer:

B=1.1636*10^{-3}T

Explanation:

Given data

d_{wires}=2.2mm=0.022m\\ I_{current}=32A\\

To find

Magnitude of the net magnetic field B

Solution

The magnitude of the net magnetic field can be find as:

B=2*u\frac{I}{2\pi r}\\ B=2*(4\pi*10^{-7}  )\frac{32}{2\pi (0.022/2)} \\ B=1.1636*10^{-3}T

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3 years ago
Which best describes what occurs when an object takes in a wave as the wave hits it?.
statuscvo [17]

Answer:

Absorption

Explanation:

7 0
1 year ago
What event will produce the greatest increase in the gravitational force between the two masses?
TiliK225 [7]

Answer:

Doubling the large mass

Explanation:

Doubling the destance bewteen the masses will simply make the gravitational force weaker

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6 0
2 years ago
The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m
IgorC [24]

Answer:

0.0360531138247 V/m

Explanation:

\rho = Resistivity of gold = 2.44\times 10^{-8}\ \Omega .m (General value)

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d = Diameter = 0.9 mm

A = Area = \dfrac{\pi}{4}d^2

E = Electric field

Resistivity is given by

\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m

The  electric field in the wire is 0.0360531138247 V/m

6 0
3 years ago
Read 2 more answers
Pleasse help
GaryK [48]

Hi,

The correct answer is letter B.

The last group contains noble gases, while both along the top and along the bottom the elements on the right are non-metals.

3 0
3 years ago
Read 2 more answers
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