Given:
mass: 100 kg
height: 500 m
1 kJ = 1000 J
gravity = 9.8 m/s²
velocity before impact: v = √2gh ; v = √2 * 9.8 m/s² * 500 m ; v = 98.99494 m/s
KE = 1/2 m v²
KE = 1/2 * 100 kg * (98.99494 m/s)²
KE = 490,000 J
Pls. see attachment.
Answer
D. move a small magnet back and forth within a section of the coiled wire.
Explanation:
i put that for the test and i got it right
Answer:
B and B
Explanation:
Question 1:
The distance is a unit of length, such as miles, meters, kilometers
The correct answer for this question would be 8m
Question 2:
Speed has a unit of length per unit of time.
The correct answer for this would be meters per second
-Chetan K
The change in gravitational potential energy due to change in position must be the change in it's kinetic energy as the system is isolated! so find out the potential energies of the two different points!
<span>PE=−[G<span>M1</span><span>M2</span>]÷R
</span><span>
Potential energy of a particle due to mass A is not affected by presence of any other mass B !</span>