Information that is given: a = -5.4m/s^2 v0 = 25 m/s --------------------- S = ? Calculate the S(distance car traveled) with the formula for velocity of decelerated motion: v^2 = v0^2 - 2aS The velocity at the end of the motion equals zero (0) because the car stops, so v=0. 0 = v0^2 - 2aS v0^2 = 2aS S = v0^2/2a S = (25 m/s)^2/(2×5.4 m/s^2) S = (25 m/s)^2/(10.8 m/s^2) S = (625 m^2/s^2)/(10.8 m/s^2) S = 57.87 m
Apparent magnitude depends mainly on the brightness of the object as seen from an observer on Earth. This is taken into account without the effects of the atmosphere.
