A tool chest has 950 N weight that acts through the midpoint of the chest. The chest is supported by feet at A and rollers at B.
1 answer:
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Answer:
a)W=12.62 kJ/mol
b)W=12.59 kJ/mol
Explanation:
At T = 100 °C the second and third virial coefficients are
B = -242.5 cm^3 mol^-1
C = 25200 cm^6 mo1^-2
Now according isothermal work of one mole methyl gas is
W=-
a=
b=
from virial equation
And
a=
b=
Now calculate V1 and V2 at given condition
Substitute given values = 1 x 10^5 , T = 373.15 and given values of coefficients we get
Solve for V1 by iterative or alternative cubic equation solver we get
Similarly solve for state 2 at P2 = 50 bar we get
Now
a=241.33
b=30780
After performing integration we get work done on the system is
W=12.62 kJ/mol
(b) for Z = 1 + B' P +C' P^2 = PV/RT by performing differential we get
dV=RT(-1/p^2+0+C')dP
Hence work done on the system is
a=
b=
by substituting given limit and P = 1 bar , P2 = 50 bar and T = 373 K we get work
W=12.59 kJ/mol
The work by differ between a and b because the conversion of constant of virial coefficients are valid only for infinite series
Answer:
16 minutes
Explanation:
This is an example of a class of problems in which two quantities start with different initial values and change at different rates. In such problems, the rates of change are generally ones that cause the values to converge.
The question usually asks when the values will be the same. The generic answer is, "when the difference in rates makes up the difference in initial values."
Here the tanks differ in initial fill height by 12 -8 = 4 ft. The rates of change differ by 0.5 -0.25 = 0.25 ft/min. The more filled tank is draining faster (important), so the fill heights will converge after ...
(4 ft)/(0.25 ft/min) = 16 min
The level in the two tanks will be the same after 16 minutes.
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<em>Additional comment</em>
The oil levels at that time will be 4 ft.
You can write two equations for height:
y = 12 -0.5x . . . . . . . height in feet after x minutes (tank A)
y = 8 -0.25x . . . . . . height in feet after x minutes (tank B)
These will be equal when ...
y = y
12 -0.5x = 8 -0.25x
4 = 0.25x . . . . . . . . . . add 0.5x -8
16 = x . . . . . . . . . . . . multiply by 4 . . . . time to equal height
The graph shows when the tanks will have equal heights and when they will be drained.
