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vodomira [7]
3 years ago
12

Unless a structural element is intended to be battered, sloped, or cambered (or some other non-conforming position), wood, steel

, and concrete should always be installed and maintained __________ , __________ , and __________. These conditions are critical in order to ensure maximum stability, structural performance and user satisfaction. Please insert the answer into the spaces provided below.
Engineering
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

stability; resistance; rigidity.

Explanation:

Okay, let us fill in the gap in the question above. Please note that the capitalized words are the missing words to fill in the gap.

"Unless a structural element is intended to be battered, sloped, or cambered (or some other non-conforming position), wood, steel, and concrete should always be installed and maintained STABILITY , RESISTANCE , and RIGIDITY. These conditions are critical in order to ensure maximum stability, structural performance and user satisfaction."

This question has to deal with buildings or say structural (civil) engineering. The definition to the missing words are given below:

STABILITY: Stability occurs when we have the center of gravity coinciding with the base of the structure.

RESISTANCE : Resistance simply means the 'tension' that is is how much the structure can resist an applied force.

RIGIDITY : RIGIDITY can also be associated with resistance and it is the property of a structure to resist bending.

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A private plane pilot is what kind of individual transportation position? professional level mid-level entry-level EPA-certified
gayaneshka [121]

Answer:

A private plane pilot is a mid-level position.

Explanation:

The six pilot certifications in the US are as follows:

  1. Sport Pilot
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From this listing, it is evident that the Private Plane Pilot is in the mid of the line so it is a mid-level position.

3 0
3 years ago
Question 5 (20 pts) The rated current of a three-phase transmission line is 300 A. The currents flowing by the line are measured
prisoha [69]

Answer:

Check the explanation

Explanation:

Question 1.

The secondary current of 250/5 amps CT when 300 amps(rated current of transmission line ) flow in TL is

(5/250 ) X 300 = 6 amps

Question 2

The correct answer to this second question is yes, when Over current relay coil will operate and relay contacts gets close, if the pickup value( Ip) of relay is set as 6 amps in relay. ( because primary current of TL is 1.2 times of CT primary)

Question 3

Tap Block figure (Fig 1) is not available/uploaded in your question.

3 0
3 years ago
Explain the differences between planned and predictive maintenance.
sveticcg [70]

Answer:

Planned maintenance refers to any scheduled activity carried out to check a machine is working ok and diagnose procedures to fix it if need it. On the other hand, predictive mainteance is all the techniques which help to define if a machine requires or not maintenance activities so far.

Explanation:

Planned maintenance is based on preventive routines to ensure a machine is working in acceptable conditions and at the same time prevent them to change to risky values performing acticities like parts replacement, cleaning,  etc. The key of this maintenance is schedule, that is to say, is a maintenance that has to be carried out constantly each certain time. Predictive maintenance is different because it is used to define if a machie needs any kind of inspection or if, on the contrary, the machine can continue operating without any intervention. The good point about predictive maintenance is the capability of telling when a maintenance is required and when is no necessarily required which is ideal to save costs.

7 0
3 years ago
The section should span between 10.9 and 13.4 cm (4.30 and 5.30 inches) as measured from the end supports and should be able to
Sergeeva-Olga [200]

Answer:

hello below is missing piece of the complete question

minimum size = 0.3 cm

answer : 0.247 N/mm2

Explanation:

Given data :

section span : 10.9 and 13.4 cm

minimum load applied evenly to the top of span  : 13 N

maximum load for each member ; 4.5 N

lets take each member to be 4.2 cm

Determine the max value of P before truss fails

Taking average value of section span ≈ 12 cm

Given minimum load distributed evenly on top of section span = 13 N  

we will calculate the value of   by applying this formula

= \frac{Wl^2}{12}  =  (0.013 * 0.0144 )/ 12  =  1.56 * 10^-5

next we will consider section ; 4.2 cm * 0.3 cm

hence Z (section modulus ) = BD^2 / 6  

                                             = ( 0.042 * 0.003^2 ) / 6  = 6.3*10^-8

Finally the max value of P( stress ) before the truss fails

= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )  

          = 0.247 N/mm2

5 0
3 years ago
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