Answer:
Hello there, please check explanations for step by step procedures to get answers.
Explanation:
Given that;
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College Engineering 10+5 pts
The switch has been in position a for a long time. At t = 0, the switch moves from position a to position b. The switch is a make-before-break type so there is no interruption of the inductor current. a. Find the expression for i(t) for t ≥ 0. b. What is the initial voltage across the inductor after the switch has been moved to position b? c. Does this initial voltage make sense in terms of circuit behavior? d. How many milliseconds after the switch has been put in position b does the inductor voltage equal 24V? e. Plot both i(t) and v(t) versus t
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Answer:
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Based on the National Electrical Code (NEC), a 450-Ampere fuse should be used to protect this polyphase (three-phase) squirrel cage inductor motor.
<u>Given the following data:</u>
- Power rating = 100-horsepower.
<h3>How to determine the correct fuse rating?</h3>
According to Table 430.52 of the National Electrical Code (NEC), a dual-element time delay fuse should be calculated at 175% (1.75) of the full-load current rating for an alternating current (AC) polyphase (three-phase) squirrel cage inductor motor.
In this scenario, the squirrel cage inductor motor didn't list a NEMA design code on its nameplate. Thus, we'll assume that the inductor motor is design B and its fuse rating is given by:
Fuse rating = 248 × 1.75 × 434
In conclusion, the nearest standard fuse size which is above the computed value listed in Section 240.6 of the National Electrical Code (NEC) is 450 amperes.
Read more on National Electrical Code here: brainly.com/question/10619436
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Answer:
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