Answer:

Explanation:
<u>Average Acceleration
</u>
Acceleration is a physical magnitude defined as the change of velocity over time. When we have experimental data, we can compute it by calculating the slope of the line in velocity vs time graph.
Note: <em>We cannot see if the time axis is numbered in increments of 1 second, and we'll assume that.
</em>
When
, the graph shows a value of
When
, the object is at rest, 
We compute the average acceleration as




Answer:
It will take 8.80 sec to fall from the building
Explanation:
We have given height pf the state building h = 380 m
Initial velocity will be 0 m /sec
So u = 0 m/sec
Acceleration due to gravity 
We have to find the fall time
According to second equation of motion 
So 

t = 8.80 sec
Like a then it would be A something I guess it goes like that
The correct answer is
B It increases.
In fact, the kinetic energy of a moving object is given by

where m is the mass of the object and v is its speed. We see that the kinetic energy is proportional to the mass and proportional to the square of the speed: in this problem, the speed of the object remains the same, while its mass increases, therefore the kinetic energy will increase as well.
For n resistors in series, the equivalent resistance is given by the sum of the resistances:

In this problem, we have three resistors, so the equivalent resistance of the load is the sum of the resistances of the three resistors: