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GREYUIT [131]
3 years ago
12

What is the momentum of a bus that weighs 13,500,000 grams traveling at 65 mph?

Physics
1 answer:
Goryan [66]3 years ago
5 0

The momentum of the bus is 3.93\cdot 10^5 kg m/s

Explanation:

The momentum of an object is given by

p=mv

where

m is the mass of the object

v is its velocity

For the bus in this problem, we have

m=13,500,000 g = 13,500 kg is its mass

v=65 mph \cdot \frac{1609 m/mi}{3600 s/h}=29.1 m/s is the velocity, converted into SI units

Substituting into the equation, we find the momentum of the bus:

p=(13,500)(29.1)=3.93\cdot 10^5 kg m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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A woman falls to the ground while wearing a parachute. The air resistance on the parachute of the parachute is 500N. If the woma
scoundrel [369]

The gravitational force on the woman is A) 500 N

Explanation:

There are two forces acting on the woman during her fall:

  • The force of gravity, F_G, acting downward
  • The air resistance, F_D, acting upward

According to Newton's second law, the net force acting on the woman is equal to the product between the woman's mass and her acceleration:

\sum F=ma

where m is the mass of the woman and a her acceleration.

The net force can be written as

\sum F = F_G - F_D

Also, we know that the woman falls at a constant velocity (5 m/s), this means that her acceleration is zero:

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Combining the equations together, we get:

F_G-F_D = 0

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5 0
3 years ago
Read 2 more answers
A 49 kg person is being dragged in their sleeping bag to the lake by a 593 N
crimeas [40]

Answer:

f = 485.62 N

Explanation:

Since, the bag is moving with some acceleration. Hence, the unbalanced force will be given as:

Unbalanced Force = Horizontal Component Applied Force - Frictional Force

Unbalanced Force = Fx - f

But, from Newtons Second Law of Motion:

Unbalanced Force = ma

comparing the equations:

ma = Fx - f

f = F Cos θ - ma

where,

f = frictional force  = ?

F = Applied force  = 593 N

m = mass of person = 49 kg

a = acceleration = 0.57 m/s²

θ = Angle with horizontal = 30°

Therefore,

f = (593 N)(Cos 30°) - (49 kg)(0.57 m/s²)

f = 513.55 N - 27.93 N

<u>f = 485.62 N</u>

6 0
3 years ago
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