Oceans are connected to all bodies of water because water molecules stick together and you can’t separate water
Answer:
wavelength is 1301.8 nm
Explanation:
Given data
energy levels n = 3 to n = 5
to find out
What is the wavelength
solution
we know wavelength formula that is given below
1/wavelength = RH(1/n1² - 1/n2²)
here we know RH value is 10973731.6 m^(-1)
so
wavelength = 1 / RH(1/n1² - 1/n2²)
wavelength = 1 / 10973731.6 (1/3² - 1/5²)
wavelength = 1.3018 ×10^-6 m
wavelength is 1301.8 nm
Answer:
Stop watch
Stop clock
Explanation:
Absolute time is time measured in definite periods such as minutes, days, and years. It can be measured uising stop watch or stop clock
Answer:
option A
Explanation:
Given,
wavelength of light,![\lambda = 560\ nm](https://tex.z-dn.net/?f=%20%5Clambda%20%3D%20560%5C%20nm)
refractive index of gasoline, n₁ = 1.40
Refractive index of water, n₂ = 1.33
thickness of the film, t = ?
Condition of constructive interference is given by
![2 n t = (m+\dfrac{1}{2})\lambda](https://tex.z-dn.net/?f=2%20n%20t%20%3D%20%28m%2B%5Cdfrac%7B1%7D%7B2%7D%29%5Clambda)
For minimum thickness of the film m = 0
From the question we can clearly observe that phase change from gasoline to air
so, n = 1.4
![2 \times 1.4 \times t = \dfrac{560}{2}](https://tex.z-dn.net/?f=2%20%5Ctimes%201.4%20%5Ctimes%20t%20%3D%20%5Cdfrac%7B560%7D%7B2%7D)
![t = 100\ nm](https://tex.z-dn.net/?f=%20t%20%3D%20100%5C%20nm)
Hence, the correct answer is option A
Answer:
Explanation:
Given that,
Height of the bridge is 20m
Initial before he throws the rock
The height is hi = 20 m
Then, final height hitting the water
hf = 0 m
Initial speed the rock is throw
Vi = 15m/s
The final speed at which the rock hits the water
Vf = 24.8 m/s
Using conservation of energy given by the question hint
Ki + Ui = Kf + Uf
Where
Ki is initial kinetic energy
Ui is initial potential energy
Kf is final kinetic energy
Uf is final potential energy
Then,
Ki + Ui = Kf + Uf
Where
Ei = Ki + Ui
Where Ei is initial energy
Ei = ½mVi² + m•g•hi
Ei = ½m × 15² + m × 9.8 × 20
Ei = 112.5m + 196m
Ei = 308.5m J
Now,
Ef = Kf + Uf
Ef = ½mVf² + m•g•hf
Ef = ½m × 24.8² + m × 9.8 × 0
Ef = 307.52m + 0
Ef = 307.52m J
Since Ef ≈ Ei, then the rock thrown from the tip of a bridge is independent of the direction of throw