Answer:
Acceleration of the crate is 0.362 m/s^2.
Explanation:
Given:
Mass of the box, m = 40 kg
Applied force, F = 15 N
Angle at which the force is applied, = 15°
We have to find the magnitude of the acceleration.
Let the acceleration be "a".
FBD is attached with where we can see the horizontal and vertical component of force.
⇒ and ⇒
⇒ ⇒
⇒ Applying concept of forces.
⇒
⇒
⇒ <em> ...Newtons second law Fnet = ma</em>
⇒
⇒ Plugging the values.
⇒ <em>...f is the friction which is zero here.</em>
⇒
⇒
Magnitude of the acceleration of the crate is 0.362 m/s^2.
Answer: Symbol A
Explanation:
The four symbols described here represent:
- Symbol A shows two dots and a line draw from one not connected to the other. --> this is an open switch. A switch is component of a circuit that is used to open/close the circuit in order to interrupt/allow the flow of current through the circuit. In this case, the switch is open, since the line does not connect the second dot.
- Symbol B shows two dots and a line draw from one connected to the other. --> this is the symbol used to represent the switch when it is closed, so it is a closed switch.
- Symbol C shows vertical lines in the pattern long, short, long, and short with a plus and minus symbol on it. --> this symbol represents a battery, which consists of two or more cells and provides the electromotive force that pushes the electrons along the circuit.
Therefore, the correct symbol representing the open switch is
Symbol A
Answer:
8 time increase in K.E.
Explanation:
Consider Mass of truck = m kg and speed = v m/s then
K.E. = 1/2 ×mv²
If mass and speed both are doubled i.e let m₀ = 2m and v₀ = 2v then
(K.E.)₀ = 1/2 ×2m(2v)²
(K.E.)₀ = 8 (1/2 × mv²) = 8 × K.E.
The correct choice is ' D ' .
These are the numbers that are missing from the set of blocks at
the top, and also the bars missing from the graph in the middle.
I have no idea what the strip at the bottom labeled "full energy spectrum"
is trying to tell us.
Answer:
The acceleration of the ball is
Explanation:
From the question we are told that
The maximum height the ball reachs is
The horizontal component of the initial velocity of the ball is
The vertical component of the initial velocity of the ball is
The vertically motion of the ball can be mathematically represented as
Here the final velocity at the maximum height is zero so
Making the acceleration the subject we have
substituting values
The negative sign shows that the direction of the acceleration is in the negative y-axis