Answer: Answer is D
I took the test little while back.
Answer:
r = 2.63 m
Explanation:
To find the distance at which the sound level is 120dB, you first calculate the intensity of the sound. You use the following formula:
(1)
β: sound level = 120dB
I: intensity of the sound
Io: threshold of hearing = 10⁻12W/m^2
You solve the equation (1) for I and replace the values of all parameters:
Next, you use the following formula for the power of the sound with intensity I, and you solve for r:
r: distance at which the sound level is 120dB
P: power of the sound = 87W
I: intensity of the sound = 1W/m^2
You replace the values of I and P for calculating r:
The distance is at 2.63m from the source of the soundr = 2.63m
Answer:
I think A. I had a similar question
Explanation:
Answer:
Explanation:
If I am not wrong
current = charge/time
All you have to take care of is the units should be in the same system
so
current = 12/(2*60) --------- 2 min = 2*60 sec
current = 12/120 = 0.1 amp
Answer:
The value is
Explanation:
From the question we are told that
The velocity which the rover is suppose to land with is
The mass of the rover and the parachute is
The drag coefficient is
The atmospheric density of Earth is
The acceleration due to gravity in Mars is
Generally the Mars atmosphere density is mathematically represented as
=>
=>
Generally the drag force on the rover and the parachute is mathematically represented as
=>
=>
Gnerally this drag force is mathematically represented as
Here A is the frontal area
So
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=>