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Kryger [21]
3 years ago
9

Molybdenum v phosphate formula

Chemistry
2 answers:
Ira Lisetskai [31]3 years ago
5 0

<u>Answer:</u> The chemical formula of the given compound is Mo_3(PO_4)_5

<u>Explanation:</u>

Molybdenum (V) phosphate is formed by the combination of molybdenum atoms and phosphate ions. This compound is ionic compound because electrons get transferred from one atom to another atom.

Molybdenum is the 42th element of the periodic table. It is a metal and it looses its electrons. The electronic configuration for this element is [Kr]4d^55s^1

This element will loose 5 electrons and forms Mo^{5+} ion.

Phosphate ion is a polyatomic ion having chemical formula of PO_4^{3-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for molybdenum (V) phosphate is Mo_3(PO_4)_5

lidiya [134]3 years ago
4 0
The formula is Mo₃(PO₄)₅
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Answer:

100 ml of a 0.300 m solution of agno3 reacts with 100 ml of a 0.300 m solution of hcl in a coffee-cup calorimeter and the temperature rises from 21.80 °c to 23.20 °c. Assuming the density and specific heat of the resulting solution is 1.00 g/ml and 4.18 j/g ∙ °c respectfully, what is the ΔH°rxn?

39.013 kJ/mol.

Explanation:

AgNO3(aq) + HCl(aq) --------------> AgCl(s) + HNO3(aq)

We can calculate the amount of heat (Q) released from the solution using the relation:

Q = m.c.ΔT,

Where, Q is the amount of heat released from the solution (Q = ??? J).

m is the mass of the solution (m of the solution = density of the solution x volume of the solution = (1.0 g/mL)(200 mL) = 200 g.

c is the specific heat capacity of the solution (c = 4.18 J/g∙°C).

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∵ ΔH°rxn = Qrxn/(no. of moles of AgNO₃).

Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of AgNO₃)/(Volume of the solution (L)).

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∴ ΔH°rxn

           = Qrxn/(no. of moles of AgNO₃)

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