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pishuonlain [190]
3 years ago
8

Need this answer in 30 minutes, What volume of ice is created from 200 cm3 of water?

Physics
2 answers:
Inessa05 [86]3 years ago
6 0

Answer:

i think about 218 cm3

Explanation:

water expands by about 9% when it freezes so 200* 1.09=218

\

Not sure if I'm correct though

Hitman42 [59]3 years ago
5 0
217.4 cc it the answer
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for example

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8 0
2 years ago
Anika asks Eva to roll a basketball and then a bowling ball to her. Which requires more force to roll, and why?
Paul [167]

It's easy to roll the the basket ball than bowling ball

It is because bowling ball is solid spherical ball which will have less moment of inertia

its moment of inertia is given as

I = \frac{2}{5}mR^2

While for the hollow ball like basketball we know that moment of inertia is given as

I' = \frac{2}{3}mR^2

so here we can see for the same mass if we take basketball then its moment of inertia is more so it is easy to roll basket ball then to roll bowling ball.

So it is easy to roll basket ball then rolling ball

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4 years ago
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Which best explains how thermal energy is transferred when someone holds a hand above a fire?
Artyom0805 [142]
Heat rises therefore the heat from the fire rises up to your hand... i didnt have any answer choices to work with sorry
5 0
3 years ago
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How does newton's second law describe the motion of an object?
vodomira [7]

Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

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Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
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