If you look at the picture you will see how, but the answer is 5 meters
If Hydrogen has 1 electron it can only have 1 outer shell (or orbital) as an electron cannot by split across shells. In general, the first shell can hold 2 electrons, the second can hold 8. Consequently, hydrogen only has 1 outer shell as it has less than 2 electrons so it does not need another shell.
Answer:
The head on Collison because you have both cars going (for the sake of it 30mph) and they both collide the energy from that is 60mph because the speed is combined with the two cars.
Answer:
Explanation:
Initial momentum
4.0(9) + 2.0(-9) = 18 kg•m/s
final momentum
4.0(-3) + 2.0(15) = 18 kg•m/s
Initial kinetic energy
½4.0(9²) + ½2.0(-9²) = 243 J
final kinetic energy
½4.0(-3²) + ½2.0(15²) = 243 J
Answer:
largest lead = 3 m
Explanation:
Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.
So, first we need to calculate the velocities of both the anchorman
given data:
Distance = d = 100 m
Time arrival for A = 9.8 s
Time arrival for B = 10.1 s
Velocity of anchorman A = D / Time arrival for A
=100/ 9.8 = 10.2 m/s
Velocity of anchorman B = D / Time arrival for B
=100/10.1 = 9.9 m/s
As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use
d = vt
= 9.9 x 9.8 = 97 m
So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.
largest lead = 100 - 97 = 3 m
So if his lead no more than 3 m anchorman A win the race.
