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REY [17]
3 years ago
9

What is the mass, in grams, of a liquid having a density of 1.50 g/ml and a volume of 3.50 liters

Mathematics
1 answer:
valina [46]3 years ago
3 0

Answer:

5250 g

Step-by-step explanation:

Given :  Density of liquid is 1.50 g/ml

             Volume of liquid is 3.50 liters

Solution :

Since 1 liter = 1000 ml

So, Volume of liquid is 3.50 liters = 3.5*1000 = 3500 ml.

Now volume = \frac{mass}{density}

3500 = \frac{mass}{1.50 }

3500 * 1.50=mass

5250 g = mass

Hence , the mass of the liquid is 5250 g.




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-100

Step-by-step explanation:

1/5 of -125 will be -25.

So, if she deposits 1/5 of what she owes, then she will deposit $25.

Her balance will then become -100 because she paid back 25.

Her new balance is -100

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The equation that passes through (3,6) and is perpendicular to 3x - 4y = - 2
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A. y=-5/3x+1

Step-by-step explanation:

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Varvara68 [4.7K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Please give me the correct answer.Only answer if you're very good at math.​
GaryK [48]

Answer:

-9 = 0.45m

Step-by-step explanation:

0.45m - 9 = 0.9m

  • ^ Subtract 0.45m from BOTH sides. so 0.9m - 0.45m... etc
  • Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
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-9 = 0.45m     <-- ANSWER

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What is the approximate area of a circle with a radius of 10 in?
yKpoI14uk [10]

<em></em>\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}

<em></em>

<em>Correction to your question text: diameter, not radius.</em>

The area of a circle is given by:

A=\pi r^2

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A=\pi\cdot\left(\dfrac{10}{2}\right)^2

Substitute and solve.

\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}

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2 years ago
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