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S_A_V [24]
3 years ago
7

Uhm i'm not too good at this so i would like an explanation and answer ples

Mathematics
2 answers:
kow [346]3 years ago
6 0

Answer:ok

Step-by-step explanation:

Three customers have accounts owing money. The table shows the account balances.

Which customer owes the least amount of money?

Customer Balance

M. Palmer –$56.72

B. Leftwich –$74.19

R. Jordan –$54.31

KiRa [710]3 years ago
5 0

Answer:

the answer is 160

Step-by-step explanation:

You might be interested in
The sales tax in Mike's home city is 8.25%. Mike buys a sweater for $49.95, two pair of slacks for $68.59 each, and a suit for $
hjlf

Answer: $50.91

Step-by-step explanation:

The following information can be gotten from the question;

Cost of sweater = $49.95,

Cost of slacks = $68.59 each,

Cost of 2 slacks = $68.59 × 2

= $137.18

Cost of suit = $429.99.

Total cost = $49.95 + $137.18 + $429.99 = $617.12

Sales tax = 8.25%

The sales tax that Mike owe will be:

= 8.25% × $617.12

= 0.0825 × $617.12

= $50.91

Mike will have to pay a sales tax of $50.91

4 0
3 years ago
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.85

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 20

            \mu = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.85-1.96 \times {\frac{0.75}{\sqrt{20} } } , 4.85+1.96 \times {\frac{0.75}{\sqrt{20} } } ]

                                            = [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.56

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 16

            \mu = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.3263 & 2.3263}  

P(-2.3263 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} <  2.3263 ) = 0.98

P( \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } } , 4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } } ]

                                            = [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0
4 years ago
8x(40+7)=(8x )+(8x7 what is the missing number
Hitman42 [59]
Well since the first expression says 8x(40+7) the answer would be 40 that is missing

Since your splitting 47 into 40 and 7 and multiplying both of them by 8 the answer would be 40
6 0
3 years ago
If the cost is a function depending on the number of sections, how much will 200 sections cost?
Scorpion4ik [409]
The awnser would be
7439$
6 0
3 years ago
Which operation should be done first?
allochka39001 [22]
If square roots includes exponents then that one is first. but if not then it is division.
7 0
3 years ago
Read 2 more answers
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