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cestrela7 [59]
3 years ago
8

A 2000 kg car accelerates from 0 to 25 m / s in 21.0 s. How much is the average power delivered by the motor? (1 hp = 746 W)

Physics
2 answers:
mash [69]3 years ago
3 0

Answer: 40.2 hp

Explanation:

The mass of the car is 2000kg.

in 21 seconds, it accelerates from 0m/s to 25m/s, so the average acceleration is:

a = (25m/s)/(21s) = 1.2 m/s^2

We know that force = mass*acceleration, then:

F = 2000kg*1.2m/s^2 = 2400N.

Now, the Power can be written as:

P = W/t where W is work = F*d (force per distance) and t is time.

then we have:

P = (F*d)/t and d/t  is the average velocity, and we know the velocity v = 25m/s, so the average velocity will be (1/2)*25m/s = 12.5m/s

P = F*12.5m/s

and the force is F = 2400N

P = 2400 N*12.5m/s = 30,000 W

and we know that 1hp = 746 W

then, P = (30,000/746) hp = 40.2 hp

DIA [1.3K]3 years ago
3 0

Answer:

P=40hp

Explanation:

Hello,

In this cased, for the given velocities, we can compute the work done by the car as shown below, considering the kinetic energy only:

W=\frac{1}{2}m(v_f^2-v_0^2)

Whereas the mass is 2000 kg, the final velocity is 25 m/s and the initial velocity is 0 m/s, therefore the work is:

W=\frac{1}{2}*2000kg*[(25\frac{m}{s})^2  -(0\frac{m}{s})^2]\\\\W=\frac{1}{2}*2000kg*625\frac{m^2}{s^2} \\\\W=6.25x10^5J

Now, the power:

P=\frac{W}{t}=\frac{6.25x10^5}{21.0s}=29762W

And in horsepower:

P=29762W*\frac{1hp}{746W} \\\\P=40hp

Best regards.

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If a student took seven science classes, his/her at score would be 1200.

<h3>What is a graph?</h3>

A graph is a relationship in which data is presented on the axes of cartesian coordinates. The presentation of the graph must be such that it is easy to read off the graph.

Now we can see that the graph is a plot of SAT scores versus the number of science classes that students take. In this case, the slope would tell us the score per subject of a student in the SAT.

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Sammy squirrel is steering his boat at a heading of 327 degree at 18mph. The current is flowing at 4mph at a heading of 60 degre
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<u>1. 18 mph 327º</u>

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  • Vector notation:

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<u>3. Addition:</u>

You add the corresponding components:

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To find the magnitude use Pythagorean theorem:

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Use the tangent ratio:

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Gain energy

good luck!
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