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Sergio039 [100]
3 years ago
15

Molecular orbital theory correctly predicts paramagnetism of oxygen gas. true or false

Physics
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer: Yes.

Explanation:

Oxygen has a bond order of two. The bond order of Oxygen molecule is calculated, where the [<em>eight valence electrons in bonding molecular orbitals</em> minus (-) <em>four valence electrons in antibonding molecular orbitals</em>]/2 in the electron configuration.

Atoms/molecules where electrons are paired are diamagnetic (repelled by both poles of a magnetic); while atoms/molecules that have one or more unpaired electrons are paramagnetic (attracted to magnetic field).

The two unpaired electrons of dioxygen molecules has made it <u>paramagnetic</u>. By pouring liquid oxygen between the poles of a strong magnet, the liquid stream will be contained by the filed and fills up the space between the poles.

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J. J. Thomson s experiments provided evidence that an atom
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J.J. Thomson's experiments provided evidence that an atom B.contains negatively charged particles.

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5 0
4 years ago
In the space below, explain why you agree or disagree with the first statement: Each person in a family has the same traits. The
bekas [8.4K]

Answer:

I disagree.

Explanation:

Yes, traits may be similar, but it all depends on the dominant and recessive alleles that are passed on.  No one person can look alike.  Even with twins, a widow's peak or close lobes can be different.

I hope this was the brainliest answer! Thank you for letting me help you.

5 0
3 years ago
Three point charges are placed on the y-axis: a charge q at y=a, a charge –2q at the origin, and a charge q at y= –a. Such an ar
den301095 [7]

Answer:

electric field   Et = kq [1 / (x-a)² -2 / x² + 1 / (x+a)²]

Explanation:

The electric field is a vector, so it must be added as vectors, in this problem both the charges and the calculation point are on the same x-axis so we can work in a single dimension, remembering that the test charge is always positive whereby the direction of the field will depend on the load under analysis, if the field is positive, if the field is negative.

 a) Let's write the electric field for each charge and the total field

       E = k q /r

With k the Coulomb constant, q the charge and r the distance of the charge to the test point

       Et = E1 + E2 + E3

       E1 = k q / (x-a)²

       E2 = k (-2q) / x²  

       E3 = k q / (x + a)²

       Et = kq [1 / (x-a)² -2 / x² + 1 / (x+a)²]

The direction of the field is along the x axis

b) To use a binomial expansion we must have an expression the form (1-x)⁻ⁿ  where x << 1, for this we take factor like x from all the equations

       Et = kq/ x² [1 / (1-a/x)² - 2 + 1 / (1+a/x)²]

We use binomial expansion

     (1+x)⁻² = 1 -nx + n (n-1) 2! x² +… x << 1

     (1-x)⁻² = 1 +nx + n (n-1) 2! x² + ...

They replace in the total field and leaving only the first terms

       

   Et =kq/x² [-2 +(1 +2 a/x + 2 (2-1)/2 (a/x)² +…) + (1 -2 a/x + 2(2-1) /2 (a/x)² +.) ]

   Et = kq/x² [a²/x² + a²/x²2] = kq /x² [2 a²/x²]

Et = k q 2a²/x⁴

point charge

Et = k q 1/x²

Dipole

E = k q a/x³

3 0
3 years ago
This problem follows up on a discussion from lecture. A wind turbine with an efficiency of 45% for converting wind energy into e
Volgvan

Answer:

4.1 m

Explanation:

10 kW = 10000 W

20mi/h = 20*1.6 km/mi = 32 km/h = 32 * 1000 (m/km) *(1/3600) hr/s = 8.89 m/s

The power yielded by the wind turbine can be calculated using the following formula

P = \frac{1}{2} \rho v^3 A C_p

where \rho = 1.2 kg/m^3 is the air density, v = 8.89 m/s is the wind speed, A is the swept area and C_p = 0.45 is the efficiency

10000 = 0.5 * 1.2 * 8.89^3 * A * 0.45

10000 = 190A

A = 10000 / 190 = 52.7 m^2

The swept area is a circle with radius r being the blade length

\pi r^2 = A = 52.7

r^2 = 52.7 / \pi = 16.79

r = \sqrt{16.79} = 4.1 m

4 0
3 years ago
Answer this please. thanks in advance!! please tel me                                                                 a christma
saw5 [17]
If 50 identical light bulbs are connected in series across
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4 years ago
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