The combustion reaction is as expressed,
CxHy + O2 --> CO2 + H2O
The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.
Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.
moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14
The empirical formula for the hydrocarbon is therefore, CH₂.
Answer:
- The speed of the wave in the rope is 2 m/s
Explanation:
1. <u>Data</u>:
a) ν = 4 Hz
b) λ = 0.5 m
c) s = ?
2. <u>Physical principles and formula</u>:
The propagation of waves in a rope is a classical example of <em>transverse waves</em>: the pulse is inflected in the <em>vertical</em> direction and the wave travels in the <em>horizontal</em> direction, i.e. the pulse or vibration is perpendicular to the motion of the media particles.
The equation that relates <em>speed (s), wavelength (λ), frequency (ν) </em>is:
- wavelength = speed × period
- wavelenfth = speed / frequency
- meter = (meter/second) / second⁻¹
3. <u>Solution</u>:
This is the answer to question 19. If it’s not clear, send me a message.
Answer:
The atomic radius of atoms generally decreases from left to right across a period. There are some small exceptions, such as the oxygen radius being slightly greater than the nitrogen radius. Within a period, protons are added to the nucleus as electrons are being added to the same principal energy level.
hope this helps!
