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2 years ago

7

Given the vectors a=6m west and b=11 m south using graphical method determine which of the following most likely represent the m

agnitude and direction of the difference vector a-b respectively

1 answer:

djverab [1.8K]2 years ago

5 0

66666 and yw a and yes let’s

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Where would you feel the most motion?

Mrac [35]

Answer:

A

Explanation:

since its the tip, you will feel it the most there.

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3 years ago

A scientist is studying a shock wave from an earthquake. What kind of wave is being studied? an electromagnetic wave a gamma ray

Anettt [7]

<span>So we want to know what kind of wave is the scientist is studying while studying earthquakes. Waves that produce earthquakes are mechanical waves. Gamma rays and radiowaves are both electromagnetic waves and don't require a medium but mechanical do. So the correct answer is mechanical waves.</span>

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3 years ago

Read 2 more answers

The potential energy of a particle as a function of position will be given as U(x) = A x2 + B x + C, where U will be in joules w

satela [25.4K]

Answer:

F = - 2 A x - B

Explanation:

The force and potential energy are related by the expression

F = - dU / dx i ^ -dU / dy j ^ - dU / dz k ^

Where i ^, j ^, k ^ are the unit vectors on the x and z axis

The potential they give us is

U (x) = A x² + B x + C

Let's calculate the derivatives

dU / dx = A 2x + B + 0

The other derivatives are zero because the potential does not depend on these variables.

Let's calculate the strength

F = - 2 A x - B

3 0

3 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

8 0

3 years ago

As a gas or liquid increases in heat, what direction will it naturally move?

miss Akunina [59]

Hello!

Answer:

When a gas gets hot it should go up because of the pressure.

Explanation:

Hope this helps!

3 0

3 years ago