Question

What is the balanced equation for the reaction of lead (II) nitrate and sodium chloride?

Answer 1

Answer:

Pb(NO3)2+2NaCl \to PbCl2+NaNO3

Explanation:

Lead(II) nitrate is $Pb(NO_{3})_{2}$

Sodium Chloride is  $NaCl$

This is a double displacement reaction. Hence anions or cations of both the compounds are displaced to form the products.

$Pb^{+2} and Cl^{-} combine to form PbCl_{2}$

$Na^{+} and \,NO_{3}^{-} combine\, to\, form\, NaNO_{3}$

Therefore the balanced equation is

$Pb(NO_{3})_{2}(aq)+2NaCl(aq) \to PbCl_{2}(s)+2NaNO_{3}(aq)$