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Pavlova-9 [17]
3 years ago
14

What is the balanced equation for the reaction of lead (II) nitrate and sodium chloride?

Chemistry
1 answer:
Sindrei [870]3 years ago
3 0

Answer:

Pb(NO3)2+2NaCl \to PbCl2+NaNO3

Explanation:

Lead(II) nitrate is $Pb(NO_{3})_{2}$

Sodium Chloride is  $NaCl$

This is a double displacement reaction. Hence anions or cations of both the compounds are displaced to form the products.

Pb^{+2}$  and $Cl^{-}$ combine to form PbCl_{2}

Na^{+} and \,NO_{3}^{-} combine\, to\, form\, NaNO_{3}

Therefore the balanced equation is

Pb(NO_{3})_{2}(aq)+2NaCl(aq) \to PbCl_{2}(s)+2NaNO_{3}(aq)

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Criss-crossing is shown in the image below.

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Hope this helps!
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