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4 years ago

What is the balanced equation for the reaction of lead (II) nitrate and sodium chloride?

Chemistry

1 answer:

Sindrei [870]4 years ago

3 0

Answer:

Pb(NO3)2+2NaCl \to PbCl2+NaNO3

Explanation:

Lead(II) nitrate is $Pb(NO_{3})_{2}$

Sodium Chloride is $NaCl$

This is a double displacement reaction. Hence anions or cations of both the compounds are displaced to form the products.

$Pb^{+2}$ and $Cl^{-}$ combine to form PbCl_{2}$

$Na^{+} and \,NO_{3}^{-} combine\, to\, form\, NaNO_{3}$

Therefore the balanced equation is

$Pb(NO_{3})_{2}(aq)+2NaCl(aq) \to PbCl_{2}(s)+2NaNO_{3}(aq)$

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For the reaction 2 H 2 O ( g ) − ⇀ ↽ − 2 H 2 ( g ) + O 2 ( g ) the equilibrium concentrations were found to be [ H 2 O ] = 0.250

Bess [88]

Answer: The equilibrium constant for the given reaction is 4.224

Explanation:

We are given:

Equilibrium concentration of water = 0.250 M

Equilibrium concentration of hydrogen gas = 0.330 M

Equilibrium concentration of oxygen gas = 0.800 M

For the given chemical reaction:

$2H_2O(g)\rightleftharpoons H_2(g)+O_2(g)$

The expression of $K_{eq}$ for above reaction follows:

$K_{eq}=\frac{[H_2][O_2]}{[H_2O]^2}$

Putting values in above expression, we get:

$K_{eq}=\frac{0.330\times 0.800}{(0.250)^2}\\\\K_{eq}=4.224$

Hence, the equilibrium constant for the given reaction is 4.224

7 0

3 years ago

1) Rank the elements, aluminum, sodium and phosphorus, in order of decreasing conductivity.

miss Akunina [59]

Conductivity is the ability of a substance to allow charge or electricity to pass through it. Metals have a lot of free electrons and are considered as good conductors while non-metals do not conduct electricity

1) In the given examples:

Al is a metal, Na is an alkali metal while P is a non-metal

The decreasing order of conductivity would be:

Al > Na > P

Both Al and Ga are metals while B is metalloid.

Among Al and Ga, Al is a solid at room temperature and a better conductor of electricity. hence the decreasing order would be:

Al > Ga > B

8 0

4 years ago

“NH4VO3” is a... Symbol Name Chemical formula

shepuryov [24]

Answer:

its a chemical formula, it has numbers and symbols

3 0

3 years ago

Read 2 more answers

Got this really tricky extra credit question I can't figure out. Anyone want to give #24 a try?

agasfer [191]

Where is the pic at ???????/????

4 0

3 years ago

Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc

marysya [2.9K]

Explanation:

1) $2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)$

$Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091$

2) $H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)$

$Kc=\frac{[H_2SO_4]}{[SO_3]^2}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3$

3) $P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)$

$Kc=\frac{1}{[O_2]^3}$

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

$Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641$

5 0

4 years ago