Visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.
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What is the anatomical position?</h3>
- Anatomical position, also known as conventional anatomical position, refers to the body's position while it is standing erect and looking forward, with each arm hanging on either side of the body and palms facing forward.
- The legs are parallel, with the feet level on the floor and forward facing.
- When explaining particular anatomical words and locations in human anatomy and physiology, the anatomical position is a standard point of reference.
- Visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.
As the description itself says, visualizing the body in its anatomical location is important because it provides a single point of reference for all observers when describing and discussing its region.
Therefore, visualizing the body in the anatomical position is significant because all observers have a common point of reference when describing and discussing its region.
Know more about the anatomical position here:
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The question you are looking for is given here:
Visualizing the body in the _____________ is significant because all observers have a common point of reference when describing and discussing its region.
Answer:
A) receding from the earth
B) 
Explanation:
- A) receding from the earth
The wavelength went from 434.1nm to 438.6nm, there was an increase in wavelength (also knowecn as redshift due to the doppler efft), this increase is due to the fact that the source that emits the radiation (the distant galaxy) is moving away and therefore the light waves it emits are "stretched", causing us to see a wavelength greater than the original.
- B)
to calculate the relative speed we use the following formula:
where 
is the speed of light: 
is the wavelength emited by the source, and
is the wavelength measured on earth.
we substitute all the values and do the calculations:
the relative speed is:
Answer:
The power is 
Explanation:
From the question we are told that
The distance from the siren is 
The intensity level is 
The threshold of hearing is 
Generally the intensity level is mathematically represented as
![\beta = 10dB * log [\frac{I}{I_o} ]](https://tex.z-dn.net/?f=%5Cbeta%20%20%3D%20%2010dB%20%2A%20log%20%5B%5Cfrac%7BI%7D%7BI_o%7D%20%5D)
Where I is the intensity at which the siren radiates the sound
substituting values
![49 = 10 * log [\frac{I}{1.0 *10^{-12}} ]](https://tex.z-dn.net/?f=49%20%20%3D%20%2010%20%2A%20log%20%5B%5Cfrac%7BI%7D%7B1.0%20%2A10%5E%7B-12%7D%7D%20%5D)
=> 
Now the amount of power the siren put out is mathematically evaluated as
Where A is the area of the siren which is taken as a sphere and it is mathematically evaluated as
So
substituting values
Answer:
-27.3 m/s
Explanation:
Given:
y₀ = 38 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2 (-9.8 m/s²) (0 m − 38 m)
v = -27.3 m/s
Or, you can solve with energy.
PE = KE
mgh = ½ mv²
v² = 2gh
v = -27.3 m/s
It keeps them back on the seat so they don't fly out the windshield.
