How might a suit of armor be a good analogy for a function of the skeletal system?
It's a frame for your body and protects organs and armor protects your body from injury
In order to overcome an object’s inertia (resistance to change), it must be acted upon by an unbalanced force, so the answer to the problem is letter C.
1. Frequency: 
The energy given is the energy per mole of particles:
1 mole contains a number of Avogadro of particles, 
, equal to
particles
So, by setting the following proportion, we can calculate the energy of a single photon:
This is the energy of a single photon; now we can calculate its frequency by using the formula:
where
is the Planck's constant
f is the photon frequency
Solving for f, we find
2. Wavelength: 
The wavelength of the photon is given by the equation:
where
is the speed of the photon (the speed of light). Substituting,
Answer:
True The grid with more slits gives more angle separation increases
True. The grating with 10 slits produces better-defined (narrower) peaks
Explanation:
Such a system can be seen as a diffraction network in this case with different number of lines per unit length, the expression for the constructive interference of a diffraction network is
d sin θ = m λ
where d is the distance between slits or lines, m the order of diffraction and λ the wavelength.
For network with 5 slits
d = 1/5 = 0.2
For the network with 10 slits
d = 1/10 = 0.1
let's calculate the separation (teat) for each one
θ = sin⁻¹ (m λ / d)
for 5 slits
θ₅ = sin⁻¹ (m λ 5)
for 10 slits
θ₁₀ = sin⁻¹ (m λ 10)
we can appreciate that for more slits the angle increases
the intensity of a series of slits is
I = I₀ sin²2 (N d/2) / sin² d/2)
when there are more slits (N) the peaks have greater intensity and are more acute (half width decreases)
let's analyze the claims
False
True The grid with more slits gives more angle separation increases
False
True The expression for the intensity of the diffraction peaks the intensity of the peaks increases with the number of slits as well as their spectral width decreases
False
If it's a distance graph, then it's a constant speed.
