A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit
ude is 29.0 t. after entering the field, the particle completes one-half of a circle and exits the field traveling due west. how much time does the particle spend traveling in the magnetic field?
1 answer:
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The correct answer is:
Let's see why.
1 amu corresponds to the mass of the proton, which is:
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
Now we can convert it into electronvolts:
So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
Let's see why.
1 amu corresponds to the mass of the proton, which is:
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
Now we can convert it into electronvolts:
So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value: