A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit
ude is 29.0 t. after entering the field, the particle completes one-half of a circle and exits the field traveling due west. how much time does the particle spend traveling in the magnetic field?
1 answer:
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Answer:
0.074m/s
Explanation:
We need the formula for conservation of momentum in a collision, this equation is given by,
Where,
= mass of ball
= mass of the person
= Velocity of ball before collision
= Velocity of the person before collision
= velocity of ball afer collision
= velocity of the person after collision
We know that after the collision, as the person as the ball have both the same velocity, then,
Re-arrenge to find ,
Our values are,
= 0.425kg
= 12m/s
= 68.5kg
= 0m/s
Substituting,
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<em>The speed of the person would be 0.074m/s after the collision between him/her and the ball</em>