A particle of mass 7.00 10-8 kg and charge 7.8-µc is traveling due east. it enters perpendicularly a magnetic field whose magnit
ude is 29.0 t. after entering the field, the particle completes one-half of a circle and exits the field traveling due west. how much time does the particle spend traveling in the magnetic field?
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Answer:
The answer is "".
Explanation:
Its minimum velocity energy is provided whenever the satellite(charge 4 q) becomes 15 m far below the square center generated by the electrode (charge q).
It's ultimate energy capacity whenever the satellite is now in the middle of the electric squares:
Potential energy shifts:
Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.
This satellite is transmitted by it system at a height of 300 km and not in orbit, any other mechanism is required to bring the satellite into space.