Solution :
Let the positive 
is along the East and the positive 
direction is along the north.
Given :
Mass of the Tesla car, 
= 
Mass of the Ford car, 
Now let the initial velocity of Tesla car in the south direction be = 
The initial momentum of Tesla car, 
Let the initial velocity of Ford car in the east direction be = 
So the initial momentum of the Ford car is 
Therefore, the initial velocity of both the cars is 
Now the final velocity of both the cars is 
So the vector form is :
Therefore the momentum after the accident is
According to the law of conservation of momentum, we know
From, 
We get, 
Therefore the speed of Tesla car before collision = 25.4 m/s
The speed of ford car before collision = 24.4 m/s
Concave mirror...as it focus the light at a given point..... concave mirror is converging !!!
Answer:
Transform active margins are associated with which type of boundary?
Transform boundary
Explanation:
The transform boundary is a boundary where one plates(crust) slides past another plate horizontally. This kind of plate movement have been detected to exist between the interaction of the North pacific plates(continental plate) and the pacific plates(oceanic plates) .
At the transform margin the crust are usually broken. But overall crust are neither created nor destroyed . The transform margin region are active as it is marked by shallow-focus earthquakes .
Along the fractured zone where this transform movement occurs is known to create extensive transform faults .Notable transform fault that exist in this kind of boundary(transform) is the San Andrea fault and Alpine Fault.
The motion of this plates can occur on a single fault or on a group of faults.
Answer:
The ball has kinetic energy
the kinetic energy is 945 J
Explanation:
Answer:
4.8967m
Explanation:
Given the following data;
M = 0.2kg
∆p = 0.58kgm/s
S(i) = 2.25m
Ratio h/w = 12/75
Firstly, we use conservation of momentum to find the velocity
Therefore, ∆p = MV
0.58kgm/s = 0.2V
V = 0.58/2
V = 2.9m/s
Then, we can use the conservation of energy to solve for maximum height the car can go
E(i) = E(f)
1/2mV² = mgh
Mass cancels out
1/2V² = gh
h = 1/2V²/g = V²/2g
h = (2.9)²/2(9.8)
h = 8.41/19.6 = 0.429m
Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.
h/w = 0.429/x
X = 0.429×75/12
X = 2.6815
Therefore, by Pythagoreans rule
S(ramp) = √2.68125²+0.429²
S(ramp) = 2.64671
Finally, S(t) = S(ramp) + S(i)
= 2.64671+2.25
= 4.8967m
