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2 years ago

Help my in science state of matter

Physics

2 answers:

Arada [10]2 years ago

7 0

I would say the last option, since with an increase in temperature, water molecules will speed up.

Bogdan [553]2 years ago

6 0

Answer:

me too last is best ig hgfvj

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Suppose kinetic energy is 4 joules of a moving object what will happen if we increase the speed twice

Artyom0805 [142]

Answer:

The kinetic energy is 16 joules.

Explanation:

Kinetic energy (E) is given by:

$E = \frac{1}{2}mv^{2}$

Where:

m: is the mass

v: is the speed

When the kinetic energy is 4 joules, the speed of the object is:

$v_{1}^{2} = \frac{2E_{1}}{m} = \frac{8}{m}$

Now, if the speed is increased twice then we have:

$E_{2} = \frac{1}{2}mv_{2}^{2} = \frac{1}{2}m(2v_{1})^{2} = \frac{1}{2}m[4(\frac{8}{m})] = 16 J$

Therefore, the kinetic energy is 4 times the initial value.

I hope it helps you!

3 0

2 years ago

A beetle with a mass of 15.0 g is initially at rest on the outer edge of a horizontal turntable that is also initially at rest.

vichka [17]

Answer:

- 8.33 x 10⁻³ rad /s ( anticlockwise)

Explanation:

The rotational movement of beetle and turntable is caused by torque generated by internal forces , we can apply conservation of angular momentum.

That is ,

I₁ ω₁ = I₂ω₂ , ω₁ and ω₂ are angular velocity of beetle and turntable respectively.

ω₁ + ω₂ = .05 radian /s ( given )

Momentum of inertia of beetle I₁ = mass x (distance from axis)²

= 15 x 10⁻³ x R² ( R is radius of the turntable )

Momentum of inertia of turntable I₂ =1/2 mass x (distance from axis)²

= 75/2 x 10⁻³ x R² ( R is radius of the turntable )

I₁ ω₁ = I₂ω₂ ,

15 x 10⁻³ x R² x ( .05 - ω₂ ) = 75/2 x 10⁻³ x R² ω₂

15 x ( .05 - ω₂ ) = 75/2 x ω₂

.75 - 15ω₂ = 37.5ω₂

.75 = 52.5 ω₂

ω₂ = - 14.3 x 10⁻³ rad /s ( anticlockwise)

7 0

2 years ago

A square loop of side length a =4.5 cm is placed a distance b = 1.1 cm from a long wire carrying a current that varies with time

sergey [27]

Answer:

a)Current will flow perpendicularly.

b)Magnitude of flux will be 2.987 N m2 C−1

3 0

2 years ago

Read 2 more answers

The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency diffe

mel-nik [20]

Question: A. The state highway patrol radar guns use a frequency of 9.15 GHz. If you're approaching a speed trap driving 30.1 m/s, what frequency shift will your FuzzFoiler 2000 radar detector see?

B. The radar gun measures the frequency of the radar pulse echoing off your car. By what percentage is the measured frequency different from the original frequency? (Enter a positive number for a frequency increase, negative for a decrease. Just enter a number, without a percent sign.)?

Answer:

The frequency change percentage is 9.94%

Explanation:

The frequency shift can be calculated as follows.

$F= \frac{V+V_{0}}{V+V_{s}}$