3 years ago

Find an equation for the nth term of the arithmetic sequence. a19 = -58, a21 = -164

Mathematics

1 answer:

Elodia [21]3 years ago

8 0

So the formula would be -1856 +98[n-1]

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A pole that is 3.2m tall casts a shadow that is 1.54m long. At the same time, a nearby building casts a shadow that is 50.75m lo

Nastasia [14]

3.2m casts 1.54m shadow.

3.2÷1.54= 160/77 (2.077922077922...)

50.75 × 160/77= 105.454545...

105m to the nearest meter.

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2 years ago

Find the missing side lengths leave your answer as a racials simplest form

luda_lava [24]

Answer:

u = 26

v = 13√3

it's 30-60-90 triangle

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3 years ago

Point c (2,2) is the center of the circle. what is the ratio of ac to the length of dc?

Nadya [2.5K]

They answer is 3::: (1:1)

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2 years ago

What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

The common ratio of 2, 10/3, 50/9 is $\frac{10}{6}$

<u>Solution:</u>

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$

Hence, the common ratio of the given series is $\frac{10}{6}$

6 0

3 years ago

The mass of earth is 5.9 x 10^24. The mass of Pluto is 13,000,000,000,000,000,000,000 kg. Compared to Pluto, how much greater is

nadya68 [22]

5.9 × 10^24 = 5,900,000,000,000,000,000,000,000 minus
13,000,000,000,000,000,000,000 equals
5,887,000,000,000,000,000,000,000 kg
which is the amount greater that Earth's mass is. you could write this problem as
5.9 × 10^24 - 13 × 10^21 = 5.887 × 10^21

7 0

3 years ago