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olga2289 [7]
3 years ago
15

What bonds are formed when electrons are shared equally?

Chemistry
1 answer:
Ratling [72]3 years ago
6 0
When electrons are shared equally, the result is a metallic bond.
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Of the following equilibria, only ________ will shift to the right in response to a decrease in volume. N2 (g) + 3H2 (g) 2NH3 (g
igomit [66]

Answer:

Of the following equilibria, only one will shift to the right in response to a decrease in volume.

N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Decrease the volume

If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.

N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

2 Fe_2O_3 (s) \rightleftharpoons 4 Fe (s) + 3O_2 (g)

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

2 SO_3 (g) \rightleftharpoons 2 SO_2 (g) + O_2 (g)

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

H_2 (g) + Cl_2 (g) \rightleftharpoons 2 HCl (g)

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

2HI (g) \rightleftharpoons H_2 (g) + I_2 (g)

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

8 0
2 years ago
Use the reaction to answer the question.
adelina 88 [10]

Answer:

its either B or C all i got hope that helps

Explanation:

3 0
2 years ago
0.5 gm of mixture of NH4Cl and NaCl was boiled with 25 ml of 0.95 N NaOH in a vessel till all the ammonia is expelled.The residu
GalinKa [24]

Answer:

72.66%

Explanation:

NH₄Cl reacts in presence of NaOH producing ammonia, NH₃, as follows:

NH₄Cl + NaOH → NaCl + NH₃ + H₂O

The residual NaOH reacts with H₂SO₄ as follows:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O.

The equivalent-gram of H₂SO₄ are:

16mL * 0.1N * 1.06 = 1.696mEq.

As the complete residual solution is 100mL but the neutralization was made only with 10mL, the mEq you need to neutralize the residual NaOH is:

1.696mEq * (100mL / 10mL) = 16.96mEq.

The mEq of NaOH you add in the first are:

25mL * 0.95mEq = 23.75mEq

That means the NaOH that reacts = moles of NH₄Cl is:

23.75mEq - 16.96mEq = 6.79mEq = 6.79mmoles NH₄Cl =

6.79x10⁻³ moles NH₄Cl

In grams (Using molar mass NH₄Cl = 53.5g/mol):

6.79x10⁻³ moles NH₄Cl * (53.5g / mol) =

0.3633g of NH₄Cl are in the original mixture.

% is:

0.3633g/ 0.5g * 100 = 72.66%

8 0
3 years ago
When substances are formed that are different from the starting substances, a physical change has occurred. True False
Sergio039 [100]
False, because physical change does not involve the formation of substances. An example of physical change is change of state e.g water freezing .It is still water if you were to melt it.
4 0
3 years ago
Read 2 more answers
A student assisting with the experiment would observe all of the following about the electron transport chain EXCEPT:A. Electron
zheka24 [161]

Answer:

C. All electron carriers are mobile and hydrophobic

Explanation:

Hello,

In this case, it is widely known that the electron carriers move inside the inner mitochondrial membrane and consequently move electrons from one to another. In such a way, they are mobile, therefore they are largely hydrophobic as long as they are inside the membrane.

For instance, the cytochrome c is a water-soluble protein in a large range, therefore, the answer is: C. All electron carriers are mobile and hydrophobic.

Best regards.

5 0
3 years ago
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