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Irina-Kira [14]
3 years ago
8

Which of the following units is an SI base unit?

Chemistry
1 answer:
Kisachek [45]3 years ago
5 0

Answer:

kg

Explanation:

kilogram√

m³×

cm×

l×

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Substance X is a compound containing 632mg of manganese and 368mg of oxygen. Substance X is shown
defon

The empirical formula : MnO₂.

<h3>Further explanation</h3>

Given

632mg of manganese(Mn) = 0.632 g

368mg of oxygen(O) = 0.368 g

M Mn = 55

M O = 16

Required

The empirical formula

Solution

You didn't include the pictures, but the steps for finding the empirical formula are generally the same

  • Find mol(mass : atomic mass)

Mn : 0.632 : 55 = 0.0115

O : 0.368 : 16 =0.023

  • Divide by the smallest mol(Mn=0.0115)

Mn : O =

\tt \dfrac{0.0115}{0.0115}\div \dfrac{0.023}{0.0115}=1\div 2

The empirical formula : MnO₂

8 0
3 years ago
The principal ingredient of glass is ______________________.
Lilit [14]
The principal ingredient of glass is quartz sand (SiO₂).
4 0
3 years ago
Part 1 of 1 - Question 3 of 20 5.0 Points 2H2 O2 - &gt; 2H2O can be classified as what type of reaction?
mart [117]
2 H₂ + O₂ = 2 H₂O


Answer B    only synthesis.

hope this helps!
7 0
3 years ago
Oil platforms may be built in the middle of the ocean. How does an oil platform work?
Korolek [52]

Answer:

A

Explanation:

There is a specific tool called an oil drill that drills into the ground and then a pipe sucks the oil up onto a vessle

8 0
3 years ago
3. Hexane (C6H-2) is combusted in oxygen
Lapatulllka [165]

Answer:

                   a)  9.5 moles of Oxygen

                    b)  1.029 × 10²⁵ Molecules

Explanation:

                    The balance chemical equation for said reaction is as follow:

                               2 C₆H₁₄ + 19 O₂   →  12 CO₂ + 14 H₂O

A)

According to equation,

              2 moles of C₆H₁₄ are reacted with  =  19 moles of O₂

So,

                   1 moles of C₆H₁₄ will react with  =  X moles of O₂

Solving for X,

                      X  =  19 moles × 1 mole / 2 moles

                       X  =  9.5 moles of Oxygen

B)

For this part first calculate moles of hexane as;

                             Moles  =  Mass / M.Mass

                             Moles  =  245.5 g / 86.18 g/mol

                             Moles  =  2.84 mole of Hexane

Secondly, find the number of moles of CO₂ as,

According to equation,

              2 moles of C₆H₁₄ produced  =  12 moles of CO₂

So,

                   2.84 moles of C₆H₁₄ will produce  =  X moles of CO₂

Solving for X,

                      X  =  12 moles × 2.84 mole / 2 moles

                       X  =  17.09 moles of CO₂

Lastly, calculate the number of molecules of CO₂ as,

Number of Molecules  =  Moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  17.09 moles × 6.022 × 10²³ molecules/mole

Number of Molecules  =  1.029 × 10²⁵ Molecules

4 0
3 years ago
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