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4 years ago

Can you answer this question please.

Physics

1 answer:

scZoUnD [109]4 years ago

6 0

Well, the lungs is one help to your body it pumps oxygen into your blood and brain the heart is a main source of your body which pump the blood in and out to the body which is the organism and the brain which is ur main control.

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A runner generates 1260 W of thermal energy. If this heat has to be removed only by evaporation, how much water does this runner

sergey [27]

Answer:0.502kg

Explanation:

F4om the relation

Power x time = mass x latent heat of vapourization

P.t=ML

1260 * 15 *60 = M * 22.6 * 10^5

M= 1134000/(22.6 *10^5)

M=0.502kg=502g

3 0

3 years ago

Matter is made up of tiny particles which can be atoms,molecules, or electrically charged particles called?.

yuradex [85]

Answer: alpha particle. i think

Explanation:

6 0

3 years ago

Amy is in-line skating. Her mass is 50 kg. She is rolling forward (north) on a flat section of road at 10 m/s. The rolling frict

Licemer1 [7]

Answer:

The right solution is "0.50 m/s²". A further explanation is provided below.

Explanation:

The given values are:

Mass,

m = 50 kg

Speed,

v = 10 m/s

Rolling friction acting backward (south),

f = 10 N

Air resistance acting backward (south),

$F_T$ = 15 N

The total force acting will be:

⇒ $F = -f-F$

On substituting the given values, we get

⇒ $=-10-15$

⇒ $=-25 \ N$

Now,

⇒ $a = \frac{F}{m}$

On substituting the given values, we get

⇒ $=\frac{-25}{50}$

⇒ $=-0.50 \ m/s^2$

The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.

4 0

3 years ago

Why does the mass of a candle decrease after burning?

34kurt

Because when a candle burns the wax is burning off so as its heated more and more wax is lost and if more wax is lost... Obviously it means that the candles mass will be lower :)

3 0

4 years ago

calculate the initial velocity of an object displaced 33 meters while accelerating 8 m/s^2 to a final velocity of 68 m/s how do

Grace [21]

Use the equation

${v_f}^2-{v_i}^2=2a\Delta x$

The final velocity $v_f$ is 68 m/s, the acceleration $a$ is 8 m/s^2, and the net displacement $\Delta x$ is 33 m, so you can solve for the initial velocity $v_i$ :

$\left(68\,\dfrac{\mathrm m}{\mathrm s}\right)^2-{v_i}^2=2\left(8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(33\,\mathrm m)$

${v_i}^2=4096\,\dfrac{\mathrm m^2}{\mathrm s^2}$

$v_i=64\,\dfrac{\mathrm m}{\mathrm s}$

8 0

3 years ago