Answer:
The minimum force that must be exerted by the mechanic at the end of a 30 cm-long wrench to loosen the nut is 110N
Explanation:
Torque = Fd sin θ
For a torque, the minimum force must be applied perpendicular to the lever arm, so that θ = 90° and sin θ = sin 90° = 1
Torque = 33 N.m
F = Force applied = ?
d = 30 cm = 0.3 m
F = Torque/d = 33/0.3 = 110 N
Answer:
34.3cm
Explanation:
Attached is the full solution
The tendency mass- less object to resist a change in its motion
Centripetal acceleration is the motion inwards towards the center of a circle. It is given by the square of velocity, divided by the radius of the circular path.
ac = v²/r, where ac is the centripetal acceleration in m/s²
Therefore,
Centripetal acceleration = 3²/20m
= 9/20m
= 0.45 m/s²
Thus, the centripetal acceleration is 0.45 m/s²
