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Ksju [112]
3 years ago
9

There are roughly 3 × 10−6 g of uranium per liter of seawater. Assuming there are 3.535 × 1020 gallons of seawater on earth, cal

culate the mass of uranium that can be extracted from seawater. (10 pts)
write governing equation, solve the problem, check your results and discuss your results.
Physics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

4 x 10^12 kg Uranium

Explanation:

As we know that 1 gallon = 3.785 L

Amount of Uranium in 1 L sea water = 3 x 10^-6 g

3.535 x 10^20 gallons = 3.535 x 10^20 x 3.785 L = 13.38 x 10^20 L

1 L of sea water contains =  3 x 10^-6 g Uranium

13.38 x 10^20 L of sea water contains = 13.38 x 10^20 x 3 x 10^-6 g Uranium

                                                              = 4 x 10^15 g = 4 x 10^12 kg Uranium

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