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Ksju [112]
4 years ago
9

There are roughly 3 × 10−6 g of uranium per liter of seawater. Assuming there are 3.535 × 1020 gallons of seawater on earth, cal

culate the mass of uranium that can be extracted from seawater. (10 pts)
write governing equation, solve the problem, check your results and discuss your results.
Physics
1 answer:
Anvisha [2.4K]4 years ago
3 0

Answer:

4 x 10^12 kg Uranium

Explanation:

As we know that 1 gallon = 3.785 L

Amount of Uranium in 1 L sea water = 3 x 10^-6 g

3.535 x 10^20 gallons = 3.535 x 10^20 x 3.785 L = 13.38 x 10^20 L

1 L of sea water contains =  3 x 10^-6 g Uranium

13.38 x 10^20 L of sea water contains = 13.38 x 10^20 x 3 x 10^-6 g Uranium

                                                              = 4 x 10^15 g = 4 x 10^12 kg Uranium

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2000 miles.

Explanation:

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choose the correct anwer 9: the range of the gravitional force is given by A: 10_2m B:10_15m C: infinite D: 10_10m​
frosja888 [35]

Answer:

The answer is C

Explanation:

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A bus driver drove her bus for 5 miles. She drove that distance in a total of 30 minutes. What was the truck driver's average sp
nexus9112 [7]

Answer:

\mathrm{b.\:}0.17\:\mathrm{miles/minute}

Explanation:

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4 0
3 years ago
A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is
Rudik [331]

Answer:

a=16.2m/s^{2}

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

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When fixed,F=o

Hence

masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}

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3 years ago
Ml(d^2θ/dt^2) =-mgθ
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The equation of motion of a pendulum is:

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\sin\theta \simeq \theta.

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\omega^2\equiv\dfrac{g}{\ell}.

We can now write:

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The solution to this differential equation is:

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This justifies that the period depends only on the pendulum's length.

4 0
3 years ago
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