Answer:
The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
Explanation:
Given that,
Mass of the meter stick, m = 0.3 kg
Center of mass is located at its 45 cm mark.
We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :
or
So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.
The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:
Figure b:
Figure c:
Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
Learn more here:brainly.com/question/19498865
