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mash [69]
3 years ago
11

Separating the electron from the proton in a hydrogen atom takes 2.18 ✕ 10−18 j of work. through what electric potential differe

nce does the electron move?
Physics
1 answer:
My name is Ann [436]3 years ago
6 0
Electric potential = work done/charge of electron = 2.18×10⁻¹⁸/1.6×10⁻¹⁹
                                                                              =  13.625 V
You might be interested in
Please help!<br> What is momentum?
VARVARA [1.3K]

Answer:

a property  of a moving body that the body has by virtue of its mass  and motion and that is equal to the product of the body's mass and velocity

Explanation:

Formula:

Momentum: Mass x Velocity

Hope it helps!

8 0
3 years ago
As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes
Mariulka [41]

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

since,

u'=\frac{5}{7}c is less than  ( \frac{3}{4}c), this means that the bullet will not hit

7 0
4 years ago
A typical 100-watt light bulb consumes 100 j of energy per second. If a light bulb converts all of this energy to 400 nm light
VladimirAG [237]

The missing question is: how many photons are produced per second?

Answer:

2.0\cdot 10^{20}

Explanation:

The energy of a photon is given by

E_1 = \frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

In this problem, the photons have wavelength

\lambda = 400 nm = 400 \cdot 10^{-9} m, so each photon has an energy of

E_1 = \frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{400\cdot 10^{-9}}=4.97\cdot 10^{-19} J

The total energy emitted by the bulb in 1 second is

E = 100 J

Therefore, the number of photons emitted per second is

n=\frac{E}{E_1}=\frac{100}{4.97\cdot 10^{-19}}=2.0\cdot 10^{20}

3 0
4 years ago
if a 5-kg bowling ball is projected upward witha velocity of 2.0 m/s, then what is the recoil velocity of the Earth(mass=6.0×10^
vitfil [10]

by the concept of momentum conservation we can say

if net force on a system of mass is ZERO then its momentum will remain conserved

Here a ball is projected upwards so if we take Ball + Earth as a system then total momentum of the system will remain conserved

Initially when ball is on the surface of earth the system has zero momentum and hence we can say after throwing the ball momentum of earth + ball must be zero

now using same equation we can say

P_{ball} + P_{earth} = 0

m_1v_1 + m_2v_2= 0

given that

m_1 = 5 kg

v_1 = 2 m/s

m_2 = 6 * 10^{24} kg

from above equation velocity of earth will be

v_2 = \frac{m_1 v_1}{m_2}

v_2 = \frac{5*2}{6 * 10^{24}}

v_2 = 1.67 * 10^{-24} m/s

so above will be the recoil speed of earth

3 0
3 years ago
What is the force of gravity?
VladimirAG [237]

Answer:

2. 4.63 x 10 to the -11th power

Explanation:

m1 = 3.1, m2= 6.3, d = 5.3, G = 6.67 × 10^-11

m1 · m2 = 3.1 · 6.3 = 19.5

d² = 5.3² = 28.1

19.5/28.1 = 0.694

(6.67 · 10^-11) · 0.694 = 4.63 × 10^-11

7 0
2 years ago
Read 2 more answers
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