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Tatiana [17]
3 years ago
14

Pers

Physics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

2.5 cm

Explanation:

Using the relation :

Refractive index = Real Depth / Apparent depth

Refractive index = 1.6

Real depth = 4cm

Virtual depth = apparent depth = x

1.6 = 4cm / x

1.6x = 4

x = 4 / 1.6

x = 2.5

Hence, virtual depth = 2.5cm

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A book is sitting on a table until I decide I needed more room sol pushed it 2 points
EleoNora [17]

Answer:

is their a picture or something

Explanation:

5 0
3 years ago
A flask contains equal masses of f2 and cl2 with a total pressure of 2.00 atm at 298k. What is the partial pressure of cl2 in th
Sindrei [870]

Answer:

Partial Pressure of F₂ = 1.30 atm

Partial pressure of Cl₂ = 0.70 atm

Explanation:

Partial pressure for gases are given by Daltons law.

Total pressure of a gas mixture = sum of the partial pressures of individual gases

Pt = P(f₂) + P(cl₂)

Partial pressure = mole fraction × total pressure

Let the mass of each gas present be m

Number of moles of F₂ = m/38 (molar mass of fluorine = 38 g/Lol

Number of moles of Cl₂ = m/71 (molar mass of Cl₂)

Mole fraction of F₂ = (m/38)/((m/38) + (m/71)) = 0.65

Mole fraction of Cl₂ = (m/71)/((m/38) + (m/71)) = 0.35 or just 1 - 0.65 = 0.35

Partial Pressure of F₂ = 0.65 × 2 = 1.30 atm

Partial pressure of Cl₂ = 0.35 × 2 = 0.70 atm

7 0
3 years ago
The two spheres pictured above have equal densities and are subject only to their mutual gravitational attraction. Which of the
kiruha [24]

Answer:

Gravitational force

Explanation:

If two spheres have equal densities and they are subject only to their mutual gravitational attraction. We need to say that the quantities that must have the same magnitude for both spheres. So, the correct option is (E) i.e. gravitational force.

It is because of Newton's third law of motion. It states that the force due to object 1 to object 2 is same as force due to object 2 to object 1. The two forces act in opposite direction.  

Hence, the correct option is (E) "Gravitational force".                        

8 0
3 years ago
17. A 25 kg block is initially at rest on a rough, horizontal surface. A horizontal force of 75 N is required to set
lapo4ka [179]

Answer:

0.30581

0.24464

Explanation:

\mu_s = Coefficient of static friction

\mu_k = Coefficient of kinetic friction

F_f = 75 N

F_k = 60 N

Normal force

F_n=mg\\\Rightarrow F_n=25\times 9.81\\\Rightarrow F_n=245.25\ N

Frictional force

F_f=\mu_sF_n\\\Rightarrow \mu_s=\frac{F_f}{F_n}\\\Rightarrow \mu_s=\frac{75}{245.25}\\\Rightarrow \mu_s=0.30581

The coefficient of static friction is 0.30581

Kinetic force

F_k=\mu_kF_n\\\Rightarrow \mu_k=\frac{F_k}{F_n}\\\Rightarrow \mu_s=\frac{60}{245.25}\\\Rightarrow \mu_s=0.24464

The coefficient of kinetic friction is 0.24464

4 0
3 years ago
two strands of DNA produced during replication are copies of each other because each strand in the double helix is
Luden [163]
The correct answer you should be looking for is complementary. :)
6 0
3 years ago
Read 2 more answers
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