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2 years ago

Which of the following is an example of a noninfectious disease?

Physics

2 answers:

Mrrafil [7]2 years ago

8 0

Answer:

D. lung cancer

Explanation:

pls mark brainliest

Scorpion4ik [409]2 years ago

3 0

D lung cancer is not infectious

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Two converging lenses, one with f = 4.0 cm and the other with f = 37 cm , are made into a telescope. What is the length of this

d1i1m1o1n [39]

Answer:

The length and the magnification of this telescope are 41 cm and 0.108.

Explanation:

Given that,

Focal length of first lens f= 4.0 cm

Focal length of other lens f'= 37 cm

We need to calculate the length of the telescope

Using formula of length

$L=f+f'$

Put the value into the formula

$L=4+37=41 cm$

We need to calculate the magnification of the telescope

Using formula of the magnification

$m=\dfrac{f}{f'}$

Put the value into the formula

$m=\dfrac{4}{37}$

$m=0.108$

Hence, The length and the magnification of this telescope are 41 cm and 0.108.

8 0

3 years ago

Astronauts aboard the ISS move at about 8000 m/s, relative to us when we look upward.How long does an astronaut need to stay abo

Luba_88 [7]

Answer:

#_time = 7.5 10⁴ s

Explanation:

In order for the astronaut to be younger than the people on earth, it follows that the speed of light has a constant speed in vacuum (c = 3 108 m / s), therefore with the expressions of special relativity we have.

t = $\frac{t_p}{ \sqrt{1- (v/c)^2} }$

where t_p is the person's own time in an immobile reference frame,

$t_{p} = t \sqrt{1 - (\frac{v}{c})^2 }$

let's calculate

we assume that the speed of the space station is constant

$t_p = 1 \sqrt{1 - \frac{8 \ 10^3}{3 \ 10^8} }$

$t_p = 1 \sqrt{1- 2.6666 \ 10^{-5}}$

t_ = 0.99998666657 s

therefore the time change is

Δt = t - t_p

Δt = 1 - 0.9998666657

Δt = 1.3333 10⁻⁵ s

this is the delay in each second, therefore we can use a direct rule of proportions. If Δt was delayed every second, how much second (#_time) is needed for a total delay of Δt = 1 s

#_time = 1 / Δt

#_time = $\frac{1}{1.3333 \ 10^{-5}}$

#_time = 7.5 10⁴ s

5 0

2 years ago

LEMME GET SOME HELO HERE PLEASE :))

natita [175]

The answer would be c

8 0

2 years ago

Read 2 more answers

A 15.4 kg block is dragged over a rough, horizontal surface by a constant force of 182 N acting at an angle of 24◦ above the hor

Dima020 [189]

Answer:

Explanation:

Considering Work done by friction is asked

Given

mass of block $m=15.4\ kg$

force $F=182\ N$

inclination $\theta =24^{\circ}$

block is displaced by $s=57.6\ m$

coefficient of kinetic friction $\mu _k=0.135$

Friction force $F_r=\mu _kN$

Normal reaction $N=mg-F\sin \theta =15.4\times 9.8-182\sin (24)$

$N=76.9\ N$

Friction Force $F_r=0.135\times 76.9=10.38\ N$

Work done by friction force

$W=f_r\cdot s$

$W=10.38\times 57.6=597.92\ N$

3 0

2 years ago

Why are you able to make someone on a swing have very large swings by only exerting very small forces on them?

Allisa [31]

Because almost all of the force is done by the weight of the person and the mechanism of the swing itself, when you push someone you only give them an increase in velocity, the acceleration comes from the weight at first and then from gravity when the person is coming down, which is why we bend our legs when coming down

3 0

2 years ago