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2 years ago

Which of the following is an example of a noninfectious disease?

Physics

2 answers:

Mrrafil [7]2 years ago

8 0

Answer:

D. lung cancer

Explanation:

pls mark brainliest

Scorpion4ik [409]2 years ago

3 0

D lung cancer is not infectious

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Which star has the highest surface temperature?

Furkat [3]

The blue star is the hottest star.

Fun Fact: The coldest stars are red

4 0

3 years ago

Determine the direction of the effective value of g⃗ at a latitude of 45 ∘ North on the Earth.

Kitty [74]

To solve this, we simply use trigonometry
the effective value of g along the 45° angle is
g eff = g / sin 45
g eff = g / (√2 / 2)
g eff = 2g / √2
g eff = g √2 ≈ 6.94 m/s²

4 0

2 years ago

in a tall building, a certain window is 500 meters above the ground.A tennis ball is catapulted horizontally out of the window w

expeople1 [14]

The tennis ball lands at a point 40.4 m from the base of the building.

The tennis ball is projected with a horizontal velocity u from a window, which is at a height y from the ground. The ball lands at a distance x from the base of the building. Let the ball take a time t to reach the ground. In the time t ,the ball falls a vertical distance y and also travel a horizontal distance x.

The initial vertical velocity of the ball is zero, since the ball is projected in the horizontal direction. The ball falls down under the action of gravitational force.

Thus, use the equation of motion,

$y=\frac{1}{2} gt^2$

rewrite the expression for t and calculate the value of t using 9.81 m/s²for g and 500 m for y.

$t=\sqrt{\frac{2y}{g} } \\ =\sqrt\frac{(2)(500m)}{9.81m/s^2} \\ =10.096 s$

The horizontal distance x is traveled using the constant velocity u since no force acts on the ball in the horizontal direction.

Therefore,

$x=ut$

Substitute 4 m/s for u and 10.096 s for t

$x=ut\\ =(4m/s)(10.096s)\\ =40.384m=40.4 m$

Thus, the ball lands at a point 40.4 m from the base of the building.

6 0

3 years ago

HELPPPPPPP!!!!!!!!!!!!!!!!

joja [24]

Point b since it gains the most height, gaining the most gravitational potential energy

Hope this helps and good luckk u can do thisss :)

6 0

2 years ago

An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if

N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.

I hope this helps!

Explanation:

8 0

2 years ago