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3 years ago

How are engineers creating clothing that can charge your cell phone. Explain the science behind their innovation.

Physics

1 answer:

soldier1979 [14.2K]3 years ago

8 0

Answer:

By the use of carbon nanotubes as the clothing material.

Explanation:

Carbon nanotubes is a technology designed by engineers that could make charging of the cell of a phone possible. It has some some required properties like it is strong, conductive and heat-resistant which are suitable for the purpose.

This technology which involves a progressive dipping of a pure cotton material into nafion polymer, then in a chemical solution of carbon nanotubes and finally in polystyrene until it becomes saturated and have a conductive property. The conductive cotton can be used to make such cloths which becomes conductive and produces some electromagnetic waves when there is a contact with sweat or fluid from the body. The waves generated can be used to charge a cell phone through radiation interaction.

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Calculate the change in velocity of a 0.070kg tennis ball hit by Serena with a force of 140 N over 0.020 s

Brilliant_brown [7]

V=at and a=F/m

140/.070 = 2000m/s^2

2000*.020 = 40m/s

The ball’s velocity increased by 40m/s.

6 0

2 years ago

When a cannon fires a cannonball, the cannon will recoil backward because the:

gulaghasi [49]

C) total linear momentum of the ball and cannon is conserved.

Basically it happens that in the beginning before there is a momentum acting on the two bodies, these are a unique system. Here the total momentum of the System is 0. However, when the positive momentum of the cannonball is added, the system will be immediately affected by a negative momentum which will pull back the cannon. Could this be extrapolated as a condition of Newton's third law.

4 0

2 years ago

A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is

velikii [3]

Answer:

(a) Length =136.58 m

(b) T=5995 N

Explanation:

for the glider in the back

T - 1900 = 700 a

for the glider in front

12000-T -1900 = 700a

add equations

12000-3800 = 1400 a

a=5.85 m/s^2

v^2 = v0^2 + 2 a x

40^2 = 2*5.85*x

Length =136.58 m

b) plug the a back into one of the previous formula

T - 1900 = 700*5.85

T=5995 N

8 0

2 years ago

A tub of water is placed in a small room and heat is removed from the room. What will most likely occur if enough heat is remove

NARA [144]

Answer:

(A)The water will freeze.

Explanation:

Heat is the energy that when transferred causes change in temperature. If heat is added to a body by some process the bodies temperature increases and if heat is removed from a body by some process the temperature reduces.

In this case if enough heat is removed from the room the internal movement of the water particles will slow down causing the water to form crystal lattice thus forming ice. So, the water will freeze.

6 0

3 years ago

Read 2 more answers

A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl

aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i: unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R= 131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

$D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2} }$

$D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2} }$

D₂= 167.21 cm

Direction of the second displacement

$\beta = tan^{-1} \frac{D_{y}}{D_{x} }$

$\beta = tan^{-1} \frac{62.18}{155.22 }$

β= 21.8°

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0

3 years ago