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Nataliya [291]
3 years ago
7

If the net force on an object is in a negative direction, what will the direction of the resulting acceleration be?

Physics
1 answer:
Verdich [7]3 years ago
5 0
Newton's 2nd law says:          Force = (mass) x (acceleration) .

I wrote Force and acceleration in bold letters because
they're both vectors ... they have size and direction.

The equation is saying that the Force and the acceleration
are both in the same direction. 
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A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
3 years ago
Which statement is true about white dwarf?
kramer

C is the correct answer

8 0
3 years ago
Read 2 more answers
Light of wavelength 436.1 nm falls on two slits spaced 0.31 mm apart. What is the required distance from the slits to the screen
kakasveta [241]

Answer:

The correct answer is "4.26 m".

Explanation:

Given:

Wavelength,

\lambda = 436.1 \ nm

or,

  =436.1\times 10^{-9} \ m

Distance,

d = 0.31 \ mm

or,

  =0.31\times 10^{-3} \ m

Distance between the 1st and 2nd dark fringes,

(y_2-y_1) = 6\times 10^{-3} \ m

As we know,

⇒ \frac{d}{L} (y_2-y_1) = \lambda

or,

⇒ L=\frac{d(y_2-y_1)}{\lambda}

By substituting the values, we get

       =\frac{0.31\times 6\times 10^{-6}}{436.1\times 10^{-9}}

       =\frac{0.31\times 6\times 10^3}{436.1}

       =\frac{1860}{436.1}

       =4.26 \ m

3 0
3 years ago
A student wants to design an experiment to study the transformation of mechanical energy. Which object can be used to investigat
Vsevolod [243]
I guess it’s the 3rd one
7 0
3 years ago
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Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?
vladimir1956 [14]

Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s

So, their average velocity is 1.6 m/s.

5 0
3 years ago
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