The dog is able to run around in a circle with a radius of9 ft.
The area of a circle is A = pi r^2
A = (3.14) (9)^2
A= (3.14)(81)
A= 254.34 sq ft
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
Answer: B
$30 + 0.18m < $55
Look at the signs!!!!
Additional mean add!
Less than <
M represent the number of miles
27 inches ......... 3/8
x inches .............8/8
<h3>x = (27×8/8)/(3/8) = 27×8/3 = 216/3 = 72 inches (father)</h3>
