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KATRIN_1 [288]
3 years ago
9

21. A toy car starts from rest and begins to

Physics
1 answer:
Bond [772]3 years ago
8 0

Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

Acceleration of the car, a = 11 m/s²

We need to find the final velocity of the toy after 6 seconds.

Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

v = u +at

v = 0 + 11 m/s² × 6 s

v = 66 m/s

So, the final velocity of the car is 66 m/s.

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Answer:

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Explanation:

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3 years ago
Imagine a star very similar to our own Sun in both size and mass. This star moves very slightly back and forth in the sky once e
Inessa05 [86]

Answer:

(c) The planet must have a mass about the same as the mass of Jupiter,

(d) The planet must be closer to the star than Earth is to the Sun.

Explanation:

Astrometry is the ideal method to detect high-mass planets that are close to their star. That is because the gravitational effect that it will have the planet over its host star will be greater. This effect can be seen as a wobble in the star as a consequence of how they orbit a common center of mass¹. The center of mass will be closer to the most massive object, So, in the case of an extrasolar planet with masses like Jupiter (Jovian), this point will be a little bit farther from the star, making the wobble more notable than in a system with a low-mass planet.          

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3 years ago
HELP A car traveling at 4m/s accelerates at a rate of .80m/s2 for 1.8s. What is its final velocity?
Semenov [28]

Answer:

148(m/s)

Explanation:

V_final = V_current + (acceleration) x (time)

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4 0
3 years ago
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When a battery, a resistor, a switch, and an inductor form a circuit and the switch is closed, the inductor acts to oppose the c
GaryK [48]

Answer:

The time constant becomes twice.

Explanation:

T = Time constant of the L-R circuit

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R = Resistance of the resistor

Time constant of the L-R circuit is given as

T = \frac{L}{R}\\

T_{1} = initial time constant of the L-R circuit = T

T_{2} = final time constant of the L-R circuit

L_{1} = Initial inductance of the inductor =  L

L_{2} = Initial inductance of the inductor =  2L

For the same resistance, the time constant depend directly on the inductance, hence

\frac{T_{1}}{T_{2}} = \frac{L_{1}}{L_{2}}\\\frac{T}{T_{2}} = \frac{L}{2L}\\\frac{T}{T_{2}} = \frac{1}{2}\\T_{2} = 2T

7 0
4 years ago
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Radda [10]

Answer:

Short circuit, closed circuit, open circuit

7 0
3 years ago
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