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KATRIN_1 [288]
3 years ago
9

21. A toy car starts from rest and begins to

Physics
1 answer:
Bond [772]3 years ago
8 0

Answer:

v = 66 m/s

Explanation:

Given that,

The initial velocity of a car, u = 0

Acceleration of the car, a = 11 m/s²

We need to find the final velocity of the toy after 6 seconds.

Let v is the final velocity. It can be calculated using first equation of motion. It is given by :

v = u +at

v = 0 + 11 m/s² × 6 s

v = 66 m/s

So, the final velocity of the car is 66 m/s.

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C. transform energy into a different from.

I hope this helps

5 0
3 years ago
A racing car can complete an 800 m long lap in 14 s. What is the speed of the<br> car?
nasty-shy [4]

Answer:

57.1 m/s

Explanation:

Speed = Distance/Time

Speed = 800/14

Speed = 57.1 m/s (3sf)

7 0
3 years ago
a 3.0 kg mass moving to the right at 1.4 m/s collides in a perfectly inelastic collision with a 2.0 kg mass initially at rest. w
Sedbober [7]

The velocity of the combined mass after the collision is 0.84 ms-1.

<u>Explanation:</u>

According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.

But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:

So as law of conservation of momentum,

                   M_{1} U_{1}+M_{2} U_{2}=M_{1} V_{1}+M_{2} V_{2}

Here M_{1} = 3 kg  and M_{2} = 2 kg are the masses of objects 1 and 2, U_{1} = 1.4 m/s  and U_{2} = 0 are the initial velocities of object 1 and object 2,  V_{1} and  V_{2} are the final velocities of the objects.

So after collision, object 1 get sticked to object 2 and move together with equal velocity V_{1} =  V_{2} = V_{f}. Thus the above equation will become,

            M_{1} U_{1}+M_{2} U_{2}=\left(M_{1}+M_{2}\right) V_{f}

So the final velocity is

              V_{f}=\frac{M_{1} U_{1}+M_{2} U_{2}}{\left(M_{1}+M_{2}\right)}

Thus,

       V_{f}=\frac{(3 \times 1.4+2 \times 0)}{(3+2)}=\frac{4.2}{5} = 0.84 ms-1.

8 0
4 years ago
In a position time graph, a curved line represents: acceleration no movement constant velocity
Mumz [18]

Answer:

acceleration or a deceleration

Explanation:

The gradient of a position -  time graph represent the velocity.

a straight line indicate a constant velocity (gradient ≠ 0)

when it is a parallel line to the time axis , it indicated no movement

when it is a curved line it indicates a changing velocity (either acceleration or a deceleration) as mentioned in the graph

4 0
3 years ago
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