Taking into account the Coulomb's Law:
![F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}](https://tex.z-dn.net/?f=F_e%20%3D%20K%5Ccdot%20%5Cfrac%7BQ_1%5Ccdot%20Q_2%7D%7Bd%5E2%7D)
If the value of Q_1 is doubled:
<span>
![F_e = K\cdot \frac{2Q_1\cdot Q_2}{d^2} = \bf 2F_e](https://tex.z-dn.net/?f=F_e%20%3D%20K%5Ccdot%20%5Cfrac%7B2Q_1%5Ccdot%20Q_2%7D%7Bd%5E2%7D%20%3D%20%5Cbf%202F_e)
The new force is two times bigger too.</span>
Answer:
that technician A is right
Explanation:
The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.
From the above it is seen that technician A is right
I think water vapour is the most important gas for understanding atmospheric processes.
correct me if i am wrong....... :)