Question

I need the work to this please

Answer 1

Answer:

  ? = 14

Step-by-step explanation:

If ∆EFG ~ ∆CBA, we have the proportion

  FG/FE = BA/BC . . . . . any pairs of corresponding sides will have the same ratio for similar triangles. (It is convenient to put the unknown in the numerator.)

  ?/18 = 21/27 . . . . . . filling in the given numbers

Multiplying by 18, we have ...

  ? = 18·21/27

  ? = 14

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If the triangles are not designated as being similar, the problem is unworkable.