In H2O, the 2 is called a

Heat, like work, is an energy transfer measured in

murzikaleks [220]

Heat, like work, is an energy transfer measured in:

<span>joules.......I hope this helps</span>

4 0

3 years ago

The reaction betwen aluminum and iron (III) oxide can

Alona [7]

Answer : The mass of $Al_2O_3$ formed will be, 468.18 grams.

Solution : Given,

Mass of Al = 124 g

Mass of $Fe_2O_3$ = 601 g

Molar mass of Al = 27 g/mole

Molar mass of $Fe_2O_3$ = 160 g/mole

Molar mass of $Al_2O_3$ = 102 g/mole

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{124g}{27g/mole}=4.59moles$

$\text{ Moles of }Fe_2O_3=\frac{\text{ Mass of }Fe_2O_3}{\text{ Molar mass of }Fe_2O_3}=\frac{601g}{160g/mole}=3.76moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe$

From the balanced reaction we conclude that

As, 2 mole of $Al$ react with 1 mole of $Fe_2O_3$

So, 4.59 moles of $O_2$ react with $\frac{4.59}{2}=2.295$ moles of $Fe_2O_3$

From this we conclude that, $Fe_2O_3$ is an excess reagent because the given moles are greater than the required moles and $Al$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$

From the reaction, we conclude that

As, 2 mole of $Al$ react to give 2 mole of $Al_2O_3$

So, 4.59 moles of $O_2$ react to give $\frac{2}{2}\times 4.59=4.59$ moles of $Al_2O_3$

Now we have to calculate the mass of $Al_2O_3$

$\text{ Mass of }Al_2O_3=\text{ Moles of }Al_2O_3\times \text{ Molar mass of }Al_2O_3$

$\text{ Mass of }Al_2O_3=(4.59moles)\times (102g/mole)=468.18g$

Therefore, the mass of $Al_2O_3$ formed will be, 468.18 grams.

3 0

3 years ago

For a compound with a molecular formula of C11H20O2, what is the formula mass?

solong [7]

The molecular formula of the compound is - C₁₁H₂₀O₂
formula mass is the sum of the products of the relative atomic masses of the elements by the number of atoms of the corresponding element
r.a.m -relative atomic mass
the elements making up the compound with their relative atomic masses are;
C - 12 r.a.m - 11 C atoms
H - 1 r.a.m - 20 H atoms
O - 16 r.a.m - 2 O atoms
the formula mass- (11 x r.a.m of C ) + (20 x r.a.m of H ) + ( 2 x r.a.m of O)
formula mass = (11 x 12) + (20 x 1) + (2 x 16)
= 132 + 20 + 32
= 184
formula mass of compound is 184

3 0

4 years ago

What is your opinion on marijuana?

jarptica [38.1K]

I think that marijuana should be legalized for recreational use. It's not really bad for you and it doesn't cause problems like violence. If marijuana was the most abused substance rather than alcohol it would be an improvement.

4 0

4 years ago

what is the mass of carbon dioxide which contain the same number of molecules as are contained in 14 gram of oxygen?

Ratling [72]

Answer:

Mass of CO2 WILL BE ~ 9.33 g

Explanation:

Moles of O2 = 14/18

Let the mass of CO2 be x

Then moles of CO2 will be = x/12

moles of CO2 = moles of O2

x/12 = 14/16

x = 9.33 grams

3 0

4 years ago