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3 years ago

In H2O, the 2 is called a

Chemistry

1 answer:

GaryK [48]3 years ago

6 0

2 hydrogen atoms hope this helps

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1. An electric power plant uses energy from burning coal to generate steam at 450 °C. The plant is cooled by 20 °C water

kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is $e=1-\frac{T_{2}}{T_{1}}$

Here Temperature of hot source $T_{1} = 450^{o}C=450+273=723 K$

and Temperature of sink $T_{1} = 20^{o}C=20+273=293 K$

Hence the efficiency is $e=1-\frac{293}{723}=0.5947=59.47%$

Now another formula for thermal efficiency Is

$e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}$

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence From $e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}$

$W=e(Q_{1})=(0.5947)(100)=59.47MJ$

Hence the of heat transferred to the river Is $Q_{2} -W = (100 -59.47=40.53$

6 0

3 years ago

At 17 °C, a 0.80 mole sample of a gas exerts a pressure of 1.2 atm. What is the volume of the container?

lapo4ka [179]

Answer:

A. 16

Explanation:

7 0

3 years ago

g In the absence of allosteric effectors, the enzyme phosphofructokinase displays Michaelis–Menten kinetics (see Fig. 7.15). The

Furkat [3]

Answer:

The value of the Michaelis–Menten constant is 0.0111 mM.

Explanation:

Michaelis–Menten 's equation:

$v_o=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}$

$V_{max}=k_{cat}[E_o]$

Where:

$v_o$ = rate of formation of products

[S] = Concatenation of substrate

$[K_m]$ = Michaelis constant

$V_{max}$ = Maximum rate achieved

$k_{cat}$ = Catalytic rate of the system

$[E_o]$ = Initial concentration of enzyme

On substituting all the given values

We have :

$\frac{v_o}{V_{max}}=0.90$

[S] = 0.10 mM

$\frac{v_o}{V_{max}}=\frac{[S]}{(K_m+[S])}$

$0.90=\frac{0.10 mM}{K_m+0.10 M}$

$K_m=0.0111 mM$

The value of the Michaelis–Menten constant is 0.0111 mM.

6 0

3 years ago

Question 8 (5 points)

Fynjy0 [20]

[H+][OH-]=10-¹⁴

We are using this formula because we need to find the H+

substitute the value given for hydronium ion for OH-

[H+][4.19×10⁵]=10-¹⁴

[H+]=10-¹⁴÷4.19×10⁵

[H+]=2.387×10-¹⁹

Then the pH of the solution will be

pH= –log¹⁰ [H+]

pH = –log¹⁰ [2.387×10-¹⁹]

pH= –log¹⁰2.387+19log¹⁰

= –0.378+19

pH =18.622

8 0

2 years ago

What is the product of 392 and 0.13592 with the correct sisignificant digits and proper scientific notation

WITCHER [35]

the correct answer is-

5.33*10

4 0

3 years ago

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