Sissy imposter among us haha
Answer:
The equilibrium shifts to the left, and the concentration of Ba2+(aq) decreases
Explanation:
Whenever a solution of an ionic substance comes into contact with another ionic compound with which it shares a common ion, the solubility of the ionic substance in solution decreases significantly.
In this case, both BaSO4 and Na2SO4 both possess the SO4^2- anion. Hence SO4^2- anion is the common ion. Given the equilibrium;
BaSO4(s) <—> Ba2+ (aq) + SO4 2- (aq), addition of Na2SO4 will decrease the solubility of BaSO4 due to the presence of a common SO4^2- anion compared to pure water.
This implies that the equilibrium will shift to the left, (more undissoctiated BaSO4) hence decreasing the Ba^2+(aq) concentration.
For the first question, salt is soluble while sand is insoluble or not dissolvable in water. The salt should have vanished or melted, but the sand stayed noticeable or visible, making a dark brown solution probably with some sand particles caught on the walls of the container when the boiling water was put in to the mixture of salt and sand. The solubility of a chemical can be disturbed by temperature, and in the case of salt in water, the hot temperature of the boiling water enhanced the salt's capability to melt in it.
For the second question, the melted or dissolved salt should have easily made its way through the filter paper and into the second container, while the undissolved and muddy sand particles is caught on the filter paper.
<u>Answer:</u>
<em>5 molecules of oxygen will be present
</em>
<u>Explanation:</u>
<em>In this reaction combustion is taking place hence there must be presence of oxygen in it.
</em>
We don't know the initial amount of carbon molecules in hydrogen molecules present hence the equation goes:-
Mass of fuel 16.74 grams, Mass of carbon dioxide is 1198 gram and water is 0.0654 remaining mass of fuel is 16.70 g. Hence amount of fuel used up is 0.04 gram
<em>
</em>
<em>Weight of products is 0.1852 and weight of oxygen is 0.1452
</em>
<em>No of molecules will be
molecules
</em>