<h2>
Relationship Between Frequency and Period</h2>
The frequency and the period are inversely proportional.
where T is the period
<h2>Solving the Question</h2>
We're given:
- <em>v</em> = 340 m/s
- <em>f</em> = 1000 Hz
Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:
<h2>Answer</h2>
You can find
1) time to hit the ground
2) initial velocity
3) speed when it hits the ground
Equations
Vx = Vxo
x = Vx * t
Vy = Vyo + gt
Vyo = 0
Vy = gt
y = yo - Vyo - gt^2 / 2
=> yo - y = gt^2 / 2
1) time to hit the ground
=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2
=> t = √1.631 s^2 = 1.28 s
2) initial velocity
Vxo = x / t = 6.5m / 1.28s = 5.08 m/s
3) speed when it hits the ground
Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s
V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2
=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
No matter what galaxy you happen to be in all the other galaxies our universe the region around Earth from which light has had time to reach us
[Assuming that you've written 3.40 kg in 'a', and not 3.90 kg]
(a) 3,400 g x <u>0.001</u> = 3.40 kg [converting grams to kilograms]
(b) 220 cm x <u>0.01</u> = <u>2.2</u> m [converting centimeters to meters]
(c) 9.42 kg x <u>1000</u> = <u>9420</u> g [converting kilograms to grams]
(d) 6.53 m x <u>100</u> = <u>653</u> cm [converting meters to centimeters]
