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viva [34]
2 years ago
5

Nellie pulls on a 10kg wagon with a constant horizontal force of 30N. If there are no other horizontal forces, what is the wagon

's acceleration
Physics
1 answer:
s2008m [1.1K]2 years ago
5 0

Answer:

The acceleration of the wagon is 3 m/s².

To calculate the acceleration of the wagon, we use the formula below.

Formula:

F = ma............. Equation 1

Where:

F = horizontal Force

m = mass of the wagon

a = acceleration of the wagon.

make a the subject of the equation

a = F/m.............. Equation 2

From the question,

Given:

F = 30 N

m = 10 kg

Substitute these values into equation 2

a = 30/10

a = 3 m/s²

Hence, the acceleration of the wagon is 3 m/s².

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Answer:

The question is incomplete, below is the complete question "A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector r with arrow = (2.00 m)i hat − (3.00 m)j + (2.00 m)k, the force is F with arrow = Fxi hat + (7.00 N)j − (5.00 N)k and the corresponding torque about the origin is vector tau = (4 N · m)i hat + (10 N · m)j + (11N · m)k.

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\left[\begin{array}{ccc}i&j&k\\2&-3&2\\ F_{x} &7&-5\end{array}\right]\\\\

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T=(18-14)i-(-12-2F_{x})j+(12+3F_{x})k\\T=4i-(-12-2F_{x})j+(12+3F_{x})k\\\\

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(4Nm)i+(10Nm)j+(11Nm)k=4i-(-12-2F_{x})j+(12+3F_{x})k\\

if we directly compare the j coordinate we have

10=-(-12-2F_{x})\\10=12+2F_{x}\\ 10-12=2F_{x}\\ F_{x}=-1N.m

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