Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.
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Answer:
10 s
Explanation:
Given:
Δx = 100 m
v₀ = 0 m/s
a = 2 m/s²
Find: t
Δx = v₀ t + ½ at²
100 m = (0 m/s) t + ½ (2 m/s²) t²
t = 10 s
C. 76 I just did the question earlier
